## anonymous one year ago Rocky simplified an expression in three steps, as shown x to the power of negative 5 multiplied by y to the power of 2, over y multiplied by x to the power of 3 multiplied by x to the power of 3 multiplied by y to the power of negative 5, the whole to the power of 2 equals x to the power of negative 10 multiplied by y to the power of 4, over y to the power of 2 multiplied by x to the power of 6 multiplied by x to the power of 6 multiplied by y to the power of negative 10 equals x to the power of negative 10 multiplied by y to the power of 4, over y to the power of negative 8 multiplied by x

1. anonymous

2. anonymous

@mathstudent55 @robtobey @freckles @mathmate @texaschic101

3. anonymous

@surjithayer

4. anonymous

hello??

5. anonymous

6. anonymous

thats what i chose

7. anonymous

The final answer is:$\frac{y^{12}}{x^{22}}$

8. anonymous

In Step 2, y^-8 is 1/y^8 . When inverted and multiplied by the numerator the exponent of y in the numerator becomes 12. The same idea applies to x^-10 in the numerator. Can you see why on you own analysis?

9. anonymous

Refer to the attachment from the Mathematica 9 program.

10. anonymous

ok i need help with one more

11. anonymous

Which of the following is a step in simplifying the expression x multiplied by y to the power of 3 over x to the power of negative 4 multiplied by y to the power of 4, the whole to the power of negative 2.? x to the power of negative 2 multiplied by y to the power of negative 6, the whole over x to the power of 8 multiplied by y to the power of negative 8. x to the power of negative 2 multiplied by y, the whole over x to the power of negative 6 multiplied by y to the power of 2. x to the power of negative 2 multiplied by y to the power of negative 6, the whole over x to the power of negative 4 multiplied by y to the power of 4. x to the power of negative 2 multiplied by y, the whole over x to the power of negative 4 multiplied by y to the power of 4.

12. anonymous

13. anonymous

Hint:$\frac{1}{\left(\frac{a}{b}\right)^2}=\frac{b^2}{a^2}$

14. anonymous

i dont understand

15. anonymous

what do you think the answer is i need to pass 8th grade and this is my final test