anonymous one year ago Which of the following could be used to calculate the area of the sector in the circle shown above? π(10in)^2 37 over 360 <---- my answer π(10in)37 over 360 π(37in)210 over 360 π(37in)10 over 360

1. anonymous

@mathmath333

2. anonymous

hmmm what lead you to think so?

3. anonymous

well i thought it was that because since r= 10 but i was a little unsure if it was right

4. anonymous

well $$\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360}$$

5. anonymous

oh ok so then it would be C right ?

6. anonymous

hmmm ahemm $$\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360} \iff \cfrac{\pi 10^2 37}{360}$$ commutative property

7. Miracrown

You're right @Moo_Moo17 It is A indeed. If angle is 360 then we get the area of the whole circle. It should be proportional to the square of the radius. $S = r ^{2}37$ And there should be angle of the sector and we know that for the circle the area is: $\pi r^2$ So, if our sector is 360 degrees we have to get full circle.

8. anonymous

oh ok thank yo so much miracrown ^w^

9. Miracrown

yw :)