Which of the following could be used to calculate the area of the sector in the circle shown above? π(10in)^2 37 over 360 <---- my answer π(10in)37 over 360 π(37in)210 over 360 π(37in)10 over 360

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Which of the following could be used to calculate the area of the sector in the circle shown above? π(10in)^2 37 over 360 <---- my answer π(10in)37 over 360 π(37in)210 over 360 π(37in)10 over 360

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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hmmm what lead you to think so?
well i thought it was that because since r= 10 but i was a little unsure if it was right

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well \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360}\)
oh ok so then it would be C right ?
hmmm ahemm \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360} \iff \cfrac{\pi 10^2 37}{360}\) commutative property
You're right @Moo_Moo17 It is A indeed. If angle is 360 then we get the area of the whole circle. It should be proportional to the square of the radius. \[S = r ^{2}37\] And there should be angle of the sector and we know that for the circle the area is: \[\pi r^2\] So, if our sector is 360 degrees we have to get full circle.
oh ok thank yo so much miracrown ^w^
yw :)

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