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anonymous

  • one year ago

Which of the following could be used to calculate the area of the sector in the circle shown above? π(10in)^2 37 over 360 <---- my answer π(10in)37 over 360 π(37in)210 over 360 π(37in)10 over 360

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  1. anonymous
    • one year ago
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    @mathmath333

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  2. jdoe0001
    • one year ago
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    hmmm what lead you to think so?

  3. anonymous
    • one year ago
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    well i thought it was that because since r= 10 but i was a little unsure if it was right

  4. jdoe0001
    • one year ago
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    well \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360}\)

  5. anonymous
    • one year ago
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    oh ok so then it would be C right ?

  6. jdoe0001
    • one year ago
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    hmmm ahemm \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360} \iff \cfrac{\pi 10^2 37}{360}\) commutative property

  7. Miracrown
    • one year ago
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    You're right @Moo_Moo17 It is A indeed. If angle is 360 then we get the area of the whole circle. It should be proportional to the square of the radius. \[S = r ^{2}37\] And there should be angle of the sector and we know that for the circle the area is: \[\pi r^2\] So, if our sector is 360 degrees we have to get full circle.

  8. anonymous
    • one year ago
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    oh ok thank yo so much miracrown ^w^

  9. Miracrown
    • one year ago
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    yw :)

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