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anonymous
 one year ago
Which of the following could be used to calculate the area of the sector in the circle shown above?
π(10in)^2 37 over 360 < my answer
π(10in)37 over 360
π(37in)210 over 360
π(37in)10 over 360
anonymous
 one year ago
Which of the following could be used to calculate the area of the sector in the circle shown above? π(10in)^2 37 over 360 < my answer π(10in)37 over 360 π(37in)210 over 360 π(37in)10 over 360

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jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmmm what lead you to think so?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well i thought it was that because since r= 10 but i was a little unsure if it was right

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok so then it would be C right ?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmmm ahemm \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=37\\ r=10 \end{cases}\implies \cfrac{37\pi 10^2}{360} \iff \cfrac{\pi 10^2 37}{360}\) commutative property

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.3You're right @Moo_Moo17 It is A indeed. If angle is 360 then we get the area of the whole circle. It should be proportional to the square of the radius. \[S = r ^{2}37\] And there should be angle of the sector and we know that for the circle the area is: \[\pi r^2\] So, if our sector is 360 degrees we have to get full circle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok thank yo so much miracrown ^w^
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