http://prntscr.com/7kjs7e last two questions, correct first if wrong, but i have no clue how to do the second one.

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http://prntscr.com/7kjs7e last two questions, correct first if wrong, but i have no clue how to do the second one.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\(\bf 12x^4y^3z^2w\div 2xy^2\implies \cfrac{12x^4y^3z^2w}{2xy^2}\implies \cfrac{6\cdot 2\cdot xxxx\cdot yyy\cdot zz}{2\cdot x\cdot yy}\) cancel anything you can, and whatever is left, is the answer :)

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on the 2nd one \(\bf 2r^2s^3t+2s^3t^2+rs^4t^3\div s^2t\implies \cfrac{2r^2s^3t+2s^3t^2+rs^4t^3}{s^2t}\) take common factor atop first
if you want to find a common factor, you could just expand the factors atop like the we did on the previous one and do say \(\bf 2r^2s^3t+2s^3t^2+rs^4t^3\div s^2t\implies \cfrac{2r^2s^3t+2s^3t^2+rs^4t^3}{s^2t} \\ \quad \\ \cfrac{2rr{\color{blue}{ ss}} s{\color{blue}{ t}}+2{\color{blue}{ ss}} st{\color{blue}{ t}}+r{\color{blue}{ ss}} ss{\color{blue}{ t}} tt}{{\color{blue}{ sst}}}\)

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