## anonymous one year ago A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle? (x + 3)2 + (y − 2)2 = 2 (x − 3)2 + (y + 2)2 = 4 (x + 3)2 + (y − 2)2 = 4 (x − 3)2 + (y + 2)2 = 2

1. anonymous

Equation of a circle is $\large (x-h)^{2}~+~(y-k)^{2}=r^{2}$ $\large (h,k)~=~Center~coordinates~of~circle$ $\large r~=~radius$ Plug in the h,k, and r, and tell me what you get :)

2. anonymous

so would r= 2 and then h and k would be (-3,2)? just wondering

3. anonymous

Right, those are all what you would plug in.

4. anonymous

oh ok (: one second

5. jdoe0001

as aforementioned $$\bf (x-{\color{brown}{ h}})^2+(y-{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ -3}},{\color{blue}{ 2}})\qquad radius={\color{purple}{ 2}}$$

6. anonymous

|dw:1435103502827:dw| is this right ?

7. anonymous

and sorry for the bad drawing lol

8. phi

yes, but your exponents should be tiny and in the "upper right"

9. anonymous

Yeah, that looks correct. Good job :)

10. anonymous

thank you ^w^

11. anonymous

$\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile$