Geometry Question - Please help ASAP! (Picture below)!

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Geometry Question - Please help ASAP! (Picture below)!

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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well its eay can u show me the attempt or do u know basic trigno
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Rishavraj can you please explain your drawing
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Wouldn't it be "C" because it's confirmed to be along with sides CA.
wht u saying???? see its mentioned tht the length of ladder is 12 feets....and makes a 45 degree angle with the building...
I had no idea that was a 12. Are you saying the possible answer can be 6/2 since it's the length of the other side... i'm sorry, this is confusing to me.
u need to find the length of AB..... so \[AC \cos 45 = AB\]
I think I understand it. I am still not so sure of my final answer, I think it's B since 24/2 would get me 12, the same as 12. I really don't understand what you by cos45.
\[\cos 45 = \frac{ 1 }{ \sqrt{2} }\] \[AB = 12 \times \frac{ 1 }{ \sqrt{2} }\]
\[12 \times \frac{ 1 }{ \sqrt{2} } = 6\sqrt{2} \]

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