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anonymous

  • one year ago

Geometry Question - Please help ASAP! (Picture below)!

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    well its eay can u show me the attempt or do u know basic trigno

  3. rishavraj
    • one year ago
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    |dw:1435119318657:dw|

  4. anonymous
    • one year ago
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    Rishavraj can you please explain your drawing

  5. rishavraj
    • one year ago
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    |dw:1435119429611:dw|

  6. anonymous
    • one year ago
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    Wouldn't it be "C" because it's confirmed to be along with sides CA.

  7. rishavraj
    • one year ago
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    wht u saying???? see its mentioned tht the length of ladder is 12 feets....and makes a 45 degree angle with the building...

  8. anonymous
    • one year ago
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    I had no idea that was a 12. Are you saying the possible answer can be 6/2 since it's the length of the other side... i'm sorry, this is confusing to me.

  9. rishavraj
    • one year ago
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    u need to find the length of AB..... so \[AC \cos 45 = AB\]

  10. anonymous
    • one year ago
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    I think I understand it. I am still not so sure of my final answer, I think it's B since 24/2 would get me 12, the same as 12. I really don't understand what you by cos45.

  11. rishavraj
    • one year ago
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    \[\cos 45 = \frac{ 1 }{ \sqrt{2} }\] \[AB = 12 \times \frac{ 1 }{ \sqrt{2} }\]

  12. rishavraj
    • one year ago
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    \[12 \times \frac{ 1 }{ \sqrt{2} } = 6\sqrt{2} \]

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