3tanx3-10tanx=0 , in the domain 180

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3tanx3-10tanx=0 , in the domain 180

Mathematics
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excuse me is it tan3x or tanx3
tanx^3
sorry i mean tanx^2

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Other answers:

so 2tanx^2 -10tanx
omggg 3tanx^2 -10tanx
Is it \[\Large 3\tan(x^2) - 10\tan(x)=0\] or Is it \[\Large 3\left(\tan(x)\right)^2 - 10\tan(x)=0\] ??
the second one
you can let z = tan(x) that gives \[\Large 3z^2 - 10z = 0\] \[\Large z(3z - 10) = 0\] agreed?
actually the x is the angle sign
yep i get those steps dk what to di next
so if z(3z-10) = 0, then either z = 0 or 3z-10 = 0 by the zero product property
re-substitute in z = tan(x) z = 0 turns into tan(x) = 0 3z-10 = 0 turns into 3*tan(x) - 10 = 0
jim we need to consider the xrange of x i also got here but the range got me confused
true, that's a good point
ok i get this whats next
solve tan(x) = 0 and 3*tan(x) - 10 = 0 and make sure 180
use the arctan function on a calculator to undo the tan function
or we can put the range
tan 0 i get 0 , for other i get 73.300
is x = 0 in the interval 180
is x = 73.3 in the interval 180
umm
yea that the part i am stuck on
if it is, then you can keep the solution if not, then add/subtract 180 until you get in the interval
being in the interval means that the number is between 180 and 360
ok 73 is
nope, 73 is not between 180 and 360
no i mean when i add 180
oh ok
excuse since its periodic the range can be taken in 0
k got the answer thank you
no problem
thanks jim
u guy can stick around ? i got more
oky woul love to in any way

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