anonymous
  • anonymous
3tanx3-10tanx=0 , in the domain 180
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
excuse me is it tan3x or tanx3
anonymous
  • anonymous
tanx^3
anonymous
  • anonymous
sorry i mean tanx^2

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anonymous
  • anonymous
so 2tanx^2 -10tanx
anonymous
  • anonymous
omggg 3tanx^2 -10tanx
anonymous
  • anonymous
@nincompoop
anonymous
  • anonymous
@abb0t
jim_thompson5910
  • jim_thompson5910
Is it \[\Large 3\tan(x^2) - 10\tan(x)=0\] or Is it \[\Large 3\left(\tan(x)\right)^2 - 10\tan(x)=0\] ??
anonymous
  • anonymous
the second one
jim_thompson5910
  • jim_thompson5910
you can let z = tan(x) that gives \[\Large 3z^2 - 10z = 0\] \[\Large z(3z - 10) = 0\] agreed?
anonymous
  • anonymous
actually the x is the angle sign
anonymous
  • anonymous
yep i get those steps dk what to di next
jim_thompson5910
  • jim_thompson5910
so if z(3z-10) = 0, then either z = 0 or 3z-10 = 0 by the zero product property
jim_thompson5910
  • jim_thompson5910
re-substitute in z = tan(x) z = 0 turns into tan(x) = 0 3z-10 = 0 turns into 3*tan(x) - 10 = 0
anonymous
  • anonymous
jim we need to consider the xrange of x i also got here but the range got me confused
jim_thompson5910
  • jim_thompson5910
true, that's a good point
anonymous
  • anonymous
ok i get this whats next
jim_thompson5910
  • jim_thompson5910
solve tan(x) = 0 and 3*tan(x) - 10 = 0 and make sure 180
jim_thompson5910
  • jim_thompson5910
use the arctan function on a calculator to undo the tan function
anonymous
  • anonymous
or we can put the range
anonymous
  • anonymous
tan 0 i get 0 , for other i get 73.300
jim_thompson5910
  • jim_thompson5910
is x = 0 in the interval 180
jim_thompson5910
  • jim_thompson5910
is x = 73.3 in the interval 180
anonymous
  • anonymous
umm
anonymous
  • anonymous
yea that the part i am stuck on
jim_thompson5910
  • jim_thompson5910
if it is, then you can keep the solution if not, then add/subtract 180 until you get in the interval
jim_thompson5910
  • jim_thompson5910
being in the interval means that the number is between 180 and 360
anonymous
  • anonymous
ok 73 is
jim_thompson5910
  • jim_thompson5910
nope, 73 is not between 180 and 360
anonymous
  • anonymous
no i mean when i add 180
jim_thompson5910
  • jim_thompson5910
oh ok
anonymous
  • anonymous
excuse since its periodic the range can be taken in 0
anonymous
  • anonymous
k got the answer thank you
jim_thompson5910
  • jim_thompson5910
no problem
anonymous
  • anonymous
thanks jim
anonymous
  • anonymous
u guy can stick around ? i got more
anonymous
  • anonymous
oky woul love to in any way

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