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JianEnriquez

  • one year ago

The minute hand of a certain clock is 6 in long. Starting from the moment when the hand is pointing straight up, how fast is the area of the sector that is swept out by the hand increasing at any instant during the next revolution of the hand?

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  1. anonymous
    • one year ago
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    area of a sector ... A = \frac{1}{2}r^2 \theta take the derivative w/r to time, t ... \frac{dA}{d\theta} = \frac{1}{2}r^2 \frac{d\theta}{dt} ... a minute hand of a clock moves at the rate of 2pi radians per hour. finish up.

  2. JianEnriquez
    • one year ago
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    ohhhh, the minute hand moves at 2pi/60mins, okay i can finish it up, thanks !

  3. anonymous
    • one year ago
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    Welcome :)

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