anonymous
  • anonymous
I need a step by step tutorial on this basically i have no background on how to solve this. Would really appreciate the help. Find the equation of the tangent line and normal line to the curve 2x^2+y^2=4 at (1, -sqrt(2)).
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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wolf1728
  • wolf1728
2x^2+y^2=4 Wouldn't you first have to put this into the form y = ???
anonymous
  • anonymous
I have to isolate y first?
wolf1728
  • wolf1728
Okay isolating y y^2=-2x^2 +4 y = Square root (-2x^2 +4 )

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anonymous
  • anonymous
then what?
wolf1728
  • wolf1728
valtajaros When someone asks a question then just leaves, I am not sticking around
wolf1728
  • wolf1728
It helps if the asker sticks around so that I can ask some things
anonymous
  • anonymous
the equation for a line passing through a point can be written as \[y-y _{1}=(x-x _{1})m\] where m is the slope of the line and \[y _{1}\] and \[x _{1}\] are the coordinates of the point that are known to us , in this case (1,-sqrt(2)) since the point lies both on the curve and on the line, the slope at this point will be same for curve and the line. we know slope=dy/dx derive the given equation and put the values of x and y as, 1 and sqrt(2) respectively, you get the value of m put the values of m, x, and y in the general equation and you get the equation for tangent
wolf1728
  • wolf1728
Okay, nitishdua31 seems aware of this so I will leave.
anonymous
  • anonymous
really sorry im having internet problems thank you tho
anonymous
  • anonymous
so first i have to get the derivative of y=sqrt(4-2x^2)
anonymous
  • anonymous
http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-tannorm-2009-1.pdf see if this can help :)
anonymous
  • anonymous
thanks man ill have a look in to this! :)
anonymous
  • anonymous
yes find the derivative and that gives you the value of slope
anonymous
  • anonymous
happy to help :D
anonymous
  • anonymous
so like sqrt(u) = du/2sqrt(u) from y = sqrt(4-2x^2) i get y' =(-4x/2sqrt(4-2x^2) = -2/sqrt(4-2x^2)
anonymous
  • anonymous
*-2x/sqrt(4-2x^2)
anonymous
  • anonymous
-2(1)/sqrt(4-2(1)^2) = -2/sqrt(2) ???
anonymous
  • anonymous
yes ! so its basically -sqrt(2)
anonymous
  • anonymous
Attachment from Mathematica 9 may be a bit short on comments.
1 Attachment
wolf1728
  • wolf1728
valtajaros "really sorry im having internet problems thank you tho" ************************************************************** sorry :-(

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