## anonymous one year ago Trig question...

• This Question is Open
1. anonymous

here's the question

2. zepdrix

Hmmm :\

3. Michele_Laino

hint: if we apply the formula for area of a triangle, then we can write this: $\Large area = \frac{1}{2}XY \times YZ \times \sin \left( {\angle XYZ} \right)$

4. anonymous

they are talking about the ambiguous angles in sin case. Your triangle should look like this : |dw:1435482187660:dw| you need to use the formula for the triangle, so since the formula is: $Area= \frac{ 1 }{ 2 }ab*sinx$ $31 = \frac{ 1 }{ 2 } *13*9 *\sin x$ $sinx = \frac{ 31 }{ \frac{ 1 }{ 2 }*9*13 } = 0.5299$ $x=\sin ^{-1}(0.5299) = 31.99°$ so since this a ambiguous case the other angle will be 180 - 31.99 = 148°