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anonymous

  • one year ago

Trig question...

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  1. anonymous
    • one year ago
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    here's the question

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  2. zepdrix
    • one year ago
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    Hmmm :\

  3. Michele_Laino
    • one year ago
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    hint: if we apply the formula for area of a triangle, then we can write this: \[\Large area = \frac{1}{2}XY \times YZ \times \sin \left( {\angle XYZ} \right)\]

  4. anonymous
    • one year ago
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    they are talking about the ambiguous angles in sin case. Your triangle should look like this : |dw:1435482187660:dw| you need to use the formula for the triangle, so since the formula is: \[Area= \frac{ 1 }{ 2 }ab*sinx\] \[31 = \frac{ 1 }{ 2 } *13*9 *\sin x\] \[sinx = \frac{ 31 }{ \frac{ 1 }{ 2 }*9*13 } = 0.5299\] \[x=\sin ^{-1}(0.5299) = 31.99°\] so since this a ambiguous case the other angle will be 180 - 31.99 = 148°

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