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there are 52 cards and 4 of them are queens so there is a 4/52 chance of getting a queen that is 1/13
I'm confused, that seems too easy
because it is :P
thats a probability of positive occurrence question right?
There are only 4 queens in the entire deck of cards Queen of Diamonds Queen of Hearts Queen of Spades QUeen of Clubs
there are only 2 colors: red (diamonds and hearts) and black (clubs and spades)
positive occurrence ?
and each suit has 2 3 4 5 6 7 8 9 10 J Q K A
Diamonds 2 3 4 5 6 7 8 9 10 J Q K A Hearts 2 3 4 5 6 7 8 9 10 J Q K A Clubs 2 3 4 5 6 7 8 9 10 J Q K A Spades 2 3 4 5 6 7 8 9 10 J Q K A
usuki, I appreciate your help but I know the suits and cards in a deck of cards, thank you!
dont over think it, there are 52 cards, and you can pick any one of them on a draw, and 4 out of the 52 are queens so 4/52 chance
which is 1/13
it just feels like what you typed is missing something. you're pulling a single card, which means you get 1 shot out of 52 to pull 1 of 4 queens
for one suit each of them does have 13 cards. one of them is the queen , so 1 in 13 chance.
look at a dice
there are 6 options on a dice
whats the chance of getting a 1?
its not a tricky question
it just occurred to me, based on the mult. choice answers I have, 1/13 can't be an answer. A)1:12 B)51;1 C)1:51 D:12:1
write 1/13 in a ratio
1:12 = 1/13
OMG I'M AN IDIOT, SORRY YOU'RE RIGHT DUH
1 as in that queen 12 rest of the cards. ?!
yes, there are 4 queens to 48 non queens s 4:48 = 1:12
that last step in probability... tsk tsk I always forget that x.x
OK, I'LL CALL THAT ONE, HAVE A COUPLE MORE