A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Find the equation of each tangent of the function f(x) = x^3+x^2+x+1 which is perpendicular
to the line 2y + x + 5 = 0.
anonymous
 one year ago
Find the equation of each tangent of the function f(x) = x^3+x^2+x+1 which is perpendicular to the line 2y + x + 5 = 0.

This Question is Closed

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0First, you should derivate the function to obtain the slope of each tangent line to it, deduce the slope of the given line and then just find the perpendicular slope. You will obtain a parametric equation and you'll have to solve for the parameters.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Take the first derivative of f(x), f'(x)=y'=slope. Let y'=0 to evaluate the value to the slope.

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.0the slope of given line is 1/2 > y = (x+5)/2 the perpendicular slope of 1/2 is 2 set derivative equal to 2 to find all points where slope of tangent line is 2 > 3x^2 +2x+1 = 2 solutions > x = 1, 1/3 equation of tangent line: \[y = f'(x_1) (x  x_1) + y_1\] \[(x_1,y_1) = (1, f(1))\] \[(x_1,y_1) = (1/3, f(1/3))\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.