A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Find the equation of each tangent of the function f(x) = x^3+x^2+x+1 which is perpendicular to the line 2y + x + 5 = 0.

  • This Question is Closed
  1. Owlcoffee
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    First, you should derivate the function to obtain the slope of each tangent line to it, deduce the slope of the given line and then just find the perpendicular slope. You will obtain a parametric equation and you'll have to solve for the parameters.

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Take the first derivative of f(x), f'(x)=y'=slope. Let y'=0 to evaluate the value to the slope.

  3. dumbcow
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the slope of given line is -1/2 --> y = -(x+5)/2 the perpendicular slope of -1/2 is 2 set derivative equal to 2 to find all points where slope of tangent line is 2 ---> 3x^2 +2x+1 = 2 solutions --> x = -1, 1/3 equation of tangent line: \[y = f'(x_1) (x - x_1) + y_1\] \[(x_1,y_1) = (-1, f(-1))\] \[(x_1,y_1) = (1/3, f(1/3))\]

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.