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anonymous
 one year ago
The sum of six terms of a geometric sequence is 63. If the first term is 3, find the common ratio.
Please explain to me the steps on how I could solve for the common ratio; thank you!
anonymous
 one year ago
The sum of six terms of a geometric sequence is 63. If the first term is 3, find the common ratio. Please explain to me the steps on how I could solve for the common ratio; thank you!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a geometric progression is one where the terms are : \[a ,ar, ar ^{2},ar ^{3}...ar ^{n}\] where a is the first term and r is the common ratio in a GP sum of n terms is given by \[(a(1r ^{n}))/(1r)\] putting this equal to 63 and a as 3, you can find the value of r
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