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anonymous

  • one year ago

The sum of six terms of a geometric sequence is -63. If the first term is 3, find the common ratio. Please explain to me the steps on how I could solve for the common ratio; thank you!

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  1. anonymous
    • one year ago
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    a geometric progression is one where the terms are : \[a ,ar, ar ^{2},ar ^{3}...ar ^{n}\] where a is the first term and r is the common ratio in a GP sum of n terms is given by \[(a(1-r ^{n}))/(1-r)\] putting this equal to -63 and a as 3, you can find the value of r

  2. anonymous
    • one year ago
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    take n as 6

  3. anonymous
    • one year ago
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    oh okay! thanks :)

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