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anonymous

  • one year ago

For the line that passes through the points (0, 2) and (-6, 0), the x-intercept is_______________and the y-intercept is _______________________________

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  1. anonymous
    • one year ago
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    I think it is, x= -6, and Y= 2... Is that right?

  2. pooja195
    • one year ago
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    We need to figure out the slope first do you know how to do that?

  3. anonymous
    • one year ago
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    To be honest, I don't think we need to go through that.... I mean I just wanted someone to check my work, because if I got it wrong, I need someone to explain it to me then....

  4. pooja195
    • one year ago
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    Thats wrong.

  5. anonymous
    • one year ago
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    Okay, I do know how to find the slope.

  6. anonymous
    • one year ago
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    I just don't have graph paper.

  7. pooja195
    • one year ago
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    You dont need graph paper.

  8. pooja195
    • one year ago
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    Use the slope Formula \[\huge~\rm~\frac{ y_2-y_1 }{ x_2-x_1}\]

  9. anonymous
    • one year ago
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    I never used that formula before? Are you sure it is right?

  10. pooja195
    • one year ago
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    Its the slope formula.

  11. anonymous
    • one year ago
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    I used y=mx+b for the slope, and on the graph paper, I used to draw the line on the squares, to get y=mx+b... i'm in 8th grade..... so... idk... but actually it is right... I turned it in to my teacher and got it right.

  12. anonymous
    • one year ago
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    x-intercept = -6 and y-intercept= 2

  13. pooja195
    • one year ago
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    Thats weird. Because thats the slope formula and to find the link you plug it into the Point slope equations and then solve and get a y=mx+b answer but whatever :)

  14. anonymous
    • one year ago
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    Okay.

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