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anonymous
 one year ago
Find the dy/dx of: 6x^(4/3) + 2y^5 = x^3y^2 + cube root of pi^5
anonymous
 one year ago
Find the dy/dx of: 6x^(4/3) + 2y^5 = x^3y^2 + cube root of pi^5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 is the correct answer (not simplified): cube root of 8 / (10y^4 + 2x^3y + 3x^2y) ?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2You guessed? or just pick one of the options and check it from me?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2Show me your work, please. Just take derivative both sides and isolate y'. Done.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 I solved for it. \[8x ^{1/3}+10y ^{4}(dy/dx)=x^32y(dy/dx)+3x^2y^2(dy/dx)+5/3\pi^^{2/3}\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2the left hand side is ok, but the right one!! first term of the right one is \(x^3y^2\), hence its derivative is \(3x^2y^2+2x^3y (dy/dx)\) the last term is a constant, hence its derivative =0 , ignore it

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2now, combine and isolate dy/dx, please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 cube root of 8 + 3x^2y^2 / (10y^4 + 2x^3y)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2the sign of denominator is not correct, it should be \(\dfrac{dy}{dx}=\dfrac{3x^2y^2\sqrt[3]{x}}{10y^42x^3y}\)
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