A community for students.
Here's the question you clicked on:
 0 viewing
elleblythe
 one year ago
Find the dy/dx of: 6x^(4/3) + 2y^5 = x^3y^2 + cube root of pi^5
elleblythe
 one year ago
Find the dy/dx of: 6x^(4/3) + 2y^5 = x^3y^2 + cube root of pi^5

This Question is Closed

elleblythe
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 is the correct answer (not simplified): cube root of 8 / (10y^4 + 2x^3y + 3x^2y) ?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2You guessed? or just pick one of the options and check it from me?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2Show me your work, please. Just take derivative both sides and isolate y'. Done.

elleblythe
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 I solved for it. \[8x ^{1/3}+10y ^{4}(dy/dx)=x^32y(dy/dx)+3x^2y^2(dy/dx)+5/3\pi^^{2/3}\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2the left hand side is ok, but the right one!! first term of the right one is \(x^3y^2\), hence its derivative is \(3x^2y^2+2x^3y (dy/dx)\) the last term is a constant, hence its derivative =0 , ignore it

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2now, combine and isolate dy/dx, please

elleblythe
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 cube root of 8 + 3x^2y^2 / (10y^4 + 2x^3y)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2the sign of denominator is not correct, it should be \(\dfrac{dy}{dx}=\dfrac{3x^2y^2\sqrt[3]{x}}{10y^42x^3y}\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.