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anonymous

  • one year ago

Please Help with a Limit Problem . Will Give a Medal

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  1. anonymous
    • one year ago
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  2. Loser66
    • one year ago
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    Where are you stuck?

  3. anonymous
    • one year ago
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    I dont know how to do the problem. I dont know where to start. Its a little confusing

  4. Loser66
    • one year ago
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    ok, tell me what does \(1^-\) mean?

  5. anonymous
    • one year ago
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    negative 1?

  6. Loser66
    • one year ago
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    nope, negative 1 is -1, not \(1^-\) Look up at your note. It is easy. I can tell you what it means but I want YOU to look it up to master the concept. Please, do it.

  7. anonymous
    • one year ago
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    x approaching 1-

  8. Loser66
    • one year ago
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    x approaches 1 from the left

  9. Loser66
    • one year ago
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    |dw:1435156237044:dw|

  10. Loser66
    • one year ago
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    now, to your problem, if x <1 , f(x) =??

  11. anonymous
    • one year ago
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    4-x

  12. Loser66
    • one year ago
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    yup, hence lim (4-x) = 4-1 =??

  13. anonymous
    • one year ago
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    you lost me

  14. Loser66
    • one year ago
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    why? you don't know 4-1= ?

  15. anonymous
    • one year ago
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    oh 3 so you just plug it in

  16. Loser66
    • one year ago
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    |dw:1435156421860:dw|

  17. Loser66
    • one year ago
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    |dw:1435156460961:dw|

  18. Loser66
    • one year ago
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    that is part a) ok? do the same with part b c is easy, just 2, nothing to do with c

  19. anonymous
    • one year ago
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    is the answer 1

  20. Loser66
    • one year ago
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    b)? how?

  21. Loser66
    • one year ago
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    for x approach 1 from the right, that is x >1, f(x) =??

  22. anonymous
    • one year ago
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    x^2+2

  23. Loser66
    • one year ago
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    hence \(lim_{x\rightarrow 1^+}(x^2+2 )=1^2+2=?\)

  24. anonymous
    • one year ago
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    3

  25. Loser66
    • one year ago
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    dat sit

  26. anonymous
    • one year ago
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    so for all the x's you would just plug in 1 so a.3 b.3 c.2

  27. Loser66
    • one year ago
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    yup

  28. anonymous
    • one year ago
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    Thank You.

  29. Loser66
    • one year ago
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    np

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