1. anonymous

2. Loser66

Where are you stuck?

3. anonymous

I dont know how to do the problem. I dont know where to start. Its a little confusing

4. Loser66

ok, tell me what does $$1^-$$ mean?

5. anonymous

negative 1?

6. Loser66

nope, negative 1 is -1, not $$1^-$$ Look up at your note. It is easy. I can tell you what it means but I want YOU to look it up to master the concept. Please, do it.

7. anonymous

x approaching 1-

8. Loser66

x approaches 1 from the left

9. Loser66

|dw:1435156237044:dw|

10. Loser66

now, to your problem, if x <1 , f(x) =??

11. anonymous

4-x

12. Loser66

yup, hence lim (4-x) = 4-1 =??

13. anonymous

you lost me

14. Loser66

why? you don't know 4-1= ?

15. anonymous

oh 3 so you just plug it in

16. Loser66

|dw:1435156421860:dw|

17. Loser66

|dw:1435156460961:dw|

18. Loser66

that is part a) ok? do the same with part b c is easy, just 2, nothing to do with c

19. anonymous

20. Loser66

b)? how?

21. Loser66

for x approach 1 from the right, that is x >1, f(x) =??

22. anonymous

x^2+2

23. Loser66

hence $$lim_{x\rightarrow 1^+}(x^2+2 )=1^2+2=?$$

24. anonymous

3

25. Loser66

dat sit

26. anonymous

so for all the x's you would just plug in 1 so a.3 b.3 c.2

27. Loser66

yup

28. anonymous

Thank You.

29. Loser66

np