A community for students.
Here's the question you clicked on:
 0 viewing
mathmath333
 one year ago
Question
mathmath333
 one year ago
Question

This Question is Closed

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align}& x\ \normalsize \text{and }\ y \ \ \text{are non negative integers such that } \hspace{.33em}\\~\\ & 4x+6y=20,\ \normalsize \text{and }\ x^2\leq \dfrac{M}{y^{2/3}} \ \normalsize \text{for all values of }\ x,y. \hspace{.33em}\\~\\ & \normalsize \text{what is the minimum value of M ?} \hspace{.33em}\\~\\ &a.)\ 2^{2/3} \hspace{.33em}\\~\\ &b.)\ 2^{1/3} \hspace{.33em}\\~\\ &c.)\ 2^{4/3} \hspace{.33em}\\~\\ &d.)\ 4^{2/3} \hspace{.33em}\\~\\ \end{align}}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1(2, 2) and (5, 0) are the only nonnegative integer solutions of 4x+6y=20

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1evaluate \(x^2 y^{2/3}\) at above solutions and pick the max value

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i m getting \(2^{8/3}\) which is not in options

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1yeah im getting the same

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1while in the book correct answer is \(\large 2^{4/3}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1is \(2^22^{2/3}\) really less than the textbook answer ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1lol what do u mean

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1(2,2) is a nonnegative integer solution to the given equation, yes ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2\leq \dfrac{M}{y^{2/3}}\] plugin \(x=2,y=2\) and \(M=\) your textbook answer

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align}& x^2\leq \dfrac{M}{y^{2/3}}\hspace{.33em}\\~\\ &x^2y^{2/3}\leq M\hspace{.33em}\\~\\ &2^2.2^{2/3}\leq M\hspace{.33em}\\~\\ &2^{2+2/3}\leq M\hspace{.33em}\\~\\ &2^{6/3+2/3}\leq M\hspace{.33em}\\~\\ &2^{8/3}\leq M\hspace{.33em}\\~\\ \end{align}}\) ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1plugin M = textbook answer

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Is \(2^{8/3} \le 2^{4/3}\) really true ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1so can we conclude textbook answer is wrong ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1thats it, spending any more time on this is a waste
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.