At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

what is the form for rotational intertia

you should have just drawn it :P

I though you'd prefer to draw it yourself :D

|dw:1435161429650:dw|

I can't add the lengths or the drawing will be nasty.

woah okay, this is confusing drawing

where is the horizontal wall?

typo not horizontal but vertical.

okay lemme try drawing it and see if i got this right

|dw:1435161896312:dw|

okay so our normal force is Fb* sin theta

did you say the resistance force are both from the frictional + moment of intertia

both of these will aid in lowering FB

|dw:1435162483641:dw|

do u know it?

You are getting it slowly.

|dw:1435162643921:dw|

mr + FBCosH = Fg , FBSinH = r

The moment at any point = 0

okk thats what i want, are u sure its just mr?

u have to add frictional force too there dont u

m = friction coefficient , r = reaction. Just those

maximum friction force = mr . So as to ease things I add mr directly.

reaction force is sintehta Fb

FBSinH = r

we need this part too though|dw:1435162931881:dw|

|dw:1435162940154:dw|

im trying to remember, please clear the concept for me

Intertial force , Maybe up my grade level. Just ignore it.

what does moment of interia give us exactly??

isnt it a torque about that point

maybe we can just completely ignored it?? there will be no rotation?

Bro, if there is inertial force. The problem 'd mention it.

oh okayy alright then lets work now lol

|dw:1435163176004:dw|

|dw:1435163282223:dw|

No need , just get the torque around (A).

oh i know, umm since its root3 r, we can figure out this angle

|dw:1435163481985:dw|

Did you notice that AC is unknown too ?

yeah

true, ugh just feels like root3 r is giving enough restrictions

Listen to me , Torque around (A) !

okayy howw

Fb, mr will be omitted

i dont really see how there can be any torque about A , should the tourque be about B

R * r sqrt(3) = FG * r so FG = sqrt(3)R R = FG/sqrt(3)

Solved.

nice, i still dont see how u did it