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anonymous
 one year ago
cos(arctan(12/5)+arctan(3/4))
anonymous
 one year ago
cos(arctan(12/5)+arctan(3/4))

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm assuming that you want to solve this in exact form by hand without a calculator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In that case, you will need to use the arctan sum formula.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@math1234 that would be correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, it is \[\tan^{1} a + \tan^{1} b = \tan^{1} \frac{ a+b }{ 1ab }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Upon combining the inside using the arctan sum formula, you can use your mentioned formula to compute the cos of the arctan.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so that gves us \[\tan^{1} \frac{ \frac{ 12 }{ 5 }+\frac{ 3 }{ 4 } }{ 1\frac{ 12 }{ 4 }*\frac{ 3 }{ 4 } }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, then you plug it into \[\cos (\tan^{1} x) = \frac{ 1 }{ \sqrt{1+x^2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where x is your fractional expression above.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\cos (\tan^{1} \frac{ 33 }{ 16 })=\frac{ 1 }{ \sqrt{1+(\frac{ 33 }{ 6 }})^{2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk where to go from here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just add the denominator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.056/65 Refer to the attachment below.
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