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2 equation, 2unknows The distance between the points is known, let it be d So the distance A and B =2d/3...1 The distance BC =d/3 By these two eqautions, both unknowns(x,y coordinates) can be found
sorry but im very confused :/
so i wou;f multiply the x coordinates by 2/5 ?
I'm not sure if what you're is okay, but surely the distance will device to 3 parts, not 5. That is, one third and two thirds
hmm I'm thinking of a different way but I get what you mean.. I'll try your method and see if I'll get the same thing.
oops sorry, I'm talking to ahmad.. and no, it shouldn't be 2/5. distance of AB= 2/3 and BC= 1/3
ohhh but wouldnt u add 2 and 3?
no, because it is not exactly referring to the actual distance. It only shows the scale on how far is A to B and C to B
ok gotcha so whats next?
oops sorry I lost my connection So we'll do the x-coordinate first, bx. (bx-ax) : (cx - bx ) = 2 : 3 (bx - 3): ( 5 - bx) = 2:3 it will be 3(bx-3) = 2(5-bx) 3bx - 9 = 10 -2 bx 5 bx = 19 bx = 19/5 Now, you do the same thing for by
ok one sec
(by-ay) : (cy-by) = 1:3 (by-4) : (11-by) = 1:3 sorry im really bad at this .. need a little help on the next step.. ):
(by-ay) : (cy-by) = 2:3 (by-4) : (11-by) = 2:3 I think the easiest way for you is turn the ratios into fraction |dw:1435173012809:dw|
ohhhh gotcha , im so dumb lol
nahh , you just need a lot of practice :)
2(11-by) = 3(by-4) 22-2by = 3by -12 22+12 -2by-2by = 3by+2by -12+12 5by /5 = 34 /5 by = 6.8 :D
good job ! :P
thank you soo much :DD i really appreciate ur help (:
well bye for now thank you again c: