A segment with endpoints A (3, 4) and C (5, 11) is partitioned by a point B such that AB and BC form a 2:3 ratio. Find B.
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@acxbox22 help :)
@Data_LG2 help please ):
2 equation, 2unknows
The distance between the points is known, let it be d
So the distance A and B =2d/3...1
The distance BC =d/3
By these two eqautions, both unknowns(x,y coordinates) can be found
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sorry but im very confused :/
so i wou;f multiply the x coordinates by 2/5 ?
I'm not sure if what you're is okay, but surely the distance will device to 3 parts, not 5. That is, one third and two thirds
@Data_LG2 try to build on that :)
hmm I'm thinking of a different way but I get what you mean.. I'll try your method and see if I'll get the same thing.
were u talking to me? @Data_LG2
oops sorry, I'm talking to ahmad..
and no, it shouldn't be 2/5.
distance of AB= 2/3 and BC= 1/3
ohhh but wouldnt u add 2 and 3?
no, because it is not exactly referring to the actual distance. It only shows the scale on how far is A to B and C to B
ok gotcha so whats next?
oops sorry I lost my connection
So we'll do the x-coordinate first, bx.
(bx-ax) : (cx - bx ) = 2 : 3
(bx - 3): ( 5 - bx) = 2:3
it will be
3(bx-3) = 2(5-bx)
3bx - 9 = 10 -2 bx
5 bx = 19
bx = 19/5
Now, you do the same thing for by
ok one sec
(by-ay) : (cy-by) = 1:3
(by-4) : (11-by) = 1:3
sorry im really bad at this .. need a little help on the next step.. ):
(by-ay) : (cy-by) = 2:3
(by-4) : (11-by) = 2:3
I think the easiest way for you is turn the ratios into fraction