anonymous
  • anonymous
Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x2 - 7x + 2 = 0
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
anonymous
  • anonymous
@dominique2525 Thats not one of the options. These are the options: {-1/2,2/3} {1/2,2/3} {1/2,3/2}
anonymous
  • anonymous
I got dominiques answer too, but how come its not one of the choices? :/

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campbell_st
  • campbell_st
I think there is a significant error in the calculations \[x =\frac{ 7 \pm \sqrt{(-7)^2 - 4 \times 6 \times 2}}{2 \times 6}\] which becomes \[x = \frac{7 \pm \sqrt{49 - 48}}{12}\]
anonymous
  • anonymous
How do i figure out what the solution set is?
campbell_st
  • campbell_st
and just to show your teacher, this quadratic can be factored multipily a and c 6 x 2 = 12 find the factors of 12 that add to -7.... they are both negative -3, -4 then write the factored equation as (6x -3)(6x -4) ------------ 6 factor the linear factors 3(2x -1) 2(3x -2) --------------- 6 remove the common factors (2x -1)(3x -2) = 0 now you can find the values
campbell_st
  • campbell_st
well to get the solution simplify the square root \[x = \frac{7 + \sqrt{1}}{12}~~~~and~~~~~ x = \frac{7 - \sqrt{1}}{12}\] what is the value of \[\sqrt{1} = ?\]
anonymous
  • anonymous
1?
campbell_st
  • campbell_st
great so you have 2 answers \[x = \frac{7 + 1}{12} ~~~~and~~~~x = \frac{7 -1}{12}\] just simplify them
anonymous
  • anonymous
@campbell_st Thank you so much!!! ugh i finally understand!!!!!
campbell_st
  • campbell_st
you made the calculation error inside the square root (-7)^2 - 4 x 6 x 2 you someone posted -49 - 48 = 97 it should 49 - 48 = 1

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