A coin is biased so that the probability of heads is 2/3. What is the probability that exactly four
heads come up when the coin is flipped seven times, assuming that the flips are independent?

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C(7, 4)(2/3)^4(1/3)^3 is the answer.
Could someone explain how they reached this conclusion?

The binomial distribution applies in this case. Have you studied the binomial distribution?

It does!
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