question

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\(\large \color{black}{\begin{align}&\{a,b\}\in \mathbb{R}\ \ \normalsize \text{if} \ 0b \hspace{.33em}\\~\\ &\normalsize \text{which of the expressions will take highest value ? } \ \hspace{.33em}\\~\\ &a.)\ a-b \hspace{.33em}\\~\\ &b.)\ a+b \hspace{.33em}\\~\\ &c.)\ \dfrac{a}{b} \hspace{.33em}\\~\\ &d.)\ \normalsize \text{cannot be determined} \hspace{.33em}\\~\\ \end{align}}\)
D, both b and are okay
0.9/0.0000000000000001 = ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Both B and C
so its c.) ?
yes it is
but book has given option d.) cannot be determined
.99/.98=? .99+.98=?
your book better have some explanation for why it cannot be determined hmm
yea wait
actually it depends on how you interpret the question, i hate these questions
cannot be determined
a+b > a/b and a/b > a+b find the intersection
Since no restrictions on a,b. My example and @ganeshie8 both worked, then it's D
\(\large \color{black}{\begin{align}\normalsize \text{Book: any of}\ (a+b) \ \text{or }\ \dfrac{a}{b} \text{could be greater thus we cannot determine this} \hspace{.33em}\\~\\ \end{align}}\)
yeah i get that, let me ask a side question : consider two functions f(x) = x^2, g(x) = -x^2+1 which function takes highest value ?
f(x)>g(x)
you can find the exact solutions too if u want
y1=a+b y2=a/b solve y1>y2 , 0b
|dw:1435174603515:dw|
3D solutions
z=x+y, z=x/y
you could say "clearly it depends on x" you could also say "clearly f(x) takes highest values because it is shooting up" depends on what the author thinks i guess
a=0.9; b=0.1: a/b > a+b a=0.99; b=0.98: a+b > a/b
here is complete solution set
my mind says its option c.)
|dw:1435174861889:dw|
so is it option d.) ?
definitely, d looks more convincing
ok thnx.
@mathmath333 how are you giving multiple medals
just like u do
i mean "how" exactly are you doing it
i click on multiple comments in a short succesion of time.

Not the answer you are looking for?

Search for more explanations.

Ask your own question