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mathmath333

  • one year ago

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align}&\{a,b\}\in \mathbb{R}\ \ \normalsize \text{if} \ 0<a<1\ \text{and } \ 0<b<1 \ \text{and }\ a>b \hspace{.33em}\\~\\ &\normalsize \text{which of the expressions will take highest value ? } \ \hspace{.33em}\\~\\ &a.)\ a-b \hspace{.33em}\\~\\ &b.)\ a+b \hspace{.33em}\\~\\ &c.)\ \dfrac{a}{b} \hspace{.33em}\\~\\ &d.)\ \normalsize \text{cannot be determined} \hspace{.33em}\\~\\ \end{align}}\)

  2. anonymous
    • one year ago
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    D, both b and are okay

  3. ganeshie8
    • one year ago
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    0.9/0.0000000000000001 = ?

  4. anonymous
    • one year ago
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    Both B and C

  5. mathmath333
    • one year ago
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    so its c.) ?

  6. ganeshie8
    • one year ago
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    yes it is

  7. mathmath333
    • one year ago
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    but book has given option d.) cannot be determined

  8. anonymous
    • one year ago
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    .99/.98=? .99+.98=?

  9. ganeshie8
    • one year ago
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    your book better have some explanation for why it cannot be determined hmm

  10. mathmath333
    • one year ago
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    yea wait

  11. ganeshie8
    • one year ago
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    actually it depends on how you interpret the question, i hate these questions

  12. dan815
    • one year ago
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    cannot be determined

  13. dan815
    • one year ago
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    a+b > a/b and a/b > a+b find the intersection

  14. anonymous
    • one year ago
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    Since no restrictions on a,b. My example and @ganeshie8 both worked, then it's D

  15. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align}\normalsize \text{Book: any of}\ (a+b) \ \text{or }\ \dfrac{a}{b} \text{could be greater thus we cannot determine this} \hspace{.33em}\\~\\ \end{align}}\)

  16. ganeshie8
    • one year ago
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    yeah i get that, let me ask a side question : consider two functions f(x) = x^2, g(x) = -x^2+1 which function takes highest value ?

  17. mathmath333
    • one year ago
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    f(x)>g(x)

  18. dan815
    • one year ago
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    you can find the exact solutions too if u want

  19. dan815
    • one year ago
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    y1=a+b y2=a/b solve y1>y2 , 0<a,b<1, a>b

  20. ganeshie8
    • one year ago
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    |dw:1435174603515:dw|

  21. dan815
    • one year ago
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    3D solutions

  22. dan815
    • one year ago
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    z=x+y, z=x/y

  23. ganeshie8
    • one year ago
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    you could say "clearly it depends on x" you could also say "clearly f(x) takes highest values because it is shooting up" depends on what the author thinks i guess

  24. ParthKohli
    • one year ago
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    a=0.9; b=0.1: a/b > a+b a=0.99; b=0.98: a+b > a/b

  25. dan815
    • one year ago
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    here is complete solution set

  26. mathmath333
    • one year ago
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    my mind says its option c.)

  27. dan815
    • one year ago
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    |dw:1435174861889:dw|

  28. mathmath333
    • one year ago
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    so is it option d.) ?

  29. ganeshie8
    • one year ago
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    definitely, d looks more convincing

  30. mathmath333
    • one year ago
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    ok thnx.

  31. ganeshie8
    • one year ago
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    @mathmath333 how are you giving multiple medals

  32. mathmath333
    • one year ago
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    just like u do

  33. ganeshie8
    • one year ago
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    i mean "how" exactly are you doing it

  34. mathmath333
    • one year ago
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    i click on multiple comments in a short succesion of time.

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