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mathmath333
 one year ago
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mathmath333
 one year ago
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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align}&\{a,b\}\in \mathbb{R}\ \ \normalsize \text{if} \ 0<a<1\ \text{and } \ 0<b<1 \ \text{and }\ a>b \hspace{.33em}\\~\\ &\normalsize \text{which of the expressions will take highest value ? } \ \hspace{.33em}\\~\\ &a.)\ ab \hspace{.33em}\\~\\ &b.)\ a+b \hspace{.33em}\\~\\ &c.)\ \dfrac{a}{b} \hspace{.33em}\\~\\ &d.)\ \normalsize \text{cannot be determined} \hspace{.33em}\\~\\ \end{align}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0D, both b and are okay

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.10.9/0.0000000000000001 = ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0but book has given option d.) cannot be determined

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1your book better have some explanation for why it cannot be determined hmm

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1actually it depends on how you interpret the question, i hate these questions

dan815
 one year ago
Best ResponseYou've already chosen the best response.1a+b > a/b and a/b > a+b find the intersection

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since no restrictions on a,b. My example and @ganeshie8 both worked, then it's D

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align}\normalsize \text{Book: any of}\ (a+b) \ \text{or }\ \dfrac{a}{b} \text{could be greater thus we cannot determine this} \hspace{.33em}\\~\\ \end{align}}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1yeah i get that, let me ask a side question : consider two functions f(x) = x^2, g(x) = x^2+1 which function takes highest value ?

dan815
 one year ago
Best ResponseYou've already chosen the best response.1you can find the exact solutions too if u want

dan815
 one year ago
Best ResponseYou've already chosen the best response.1y1=a+b y2=a/b solve y1>y2 , 0<a,b<1, a>b

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435174603515:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1you could say "clearly it depends on x" you could also say "clearly f(x) takes highest values because it is shooting up" depends on what the author thinks i guess

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1a=0.9; b=0.1: a/b > a+b a=0.99; b=0.98: a+b > a/b

dan815
 one year ago
Best ResponseYou've already chosen the best response.1here is complete solution set

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0my mind says its option c.)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0so is it option d.) ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1definitely, d looks more convincing

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1@mathmath333 how are you giving multiple medals

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1i mean "how" exactly are you doing it

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0i click on multiple comments in a short succesion of time.
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