anonymous
  • anonymous
Which expressions are equivalent to 4(4x + 2y + x − y)? 4(5x + 3y) and 20x + 12y 4(5x + y) and 20x + 4y 4(3x + y) and 12x + 4y 4(3x + 3y) and 12x + 12y
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
idk how to do this
anonymous
  • anonymous
yea I am pretty bad myself
anonymous
  • anonymous
what grade work is this

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More answers

anonymous
  • anonymous
@pooja195 @math1234
anonymous
  • anonymous
6 (advanced) I do mostly 8th or 9th tho
anonymous
  • anonymous
@horsegirl27 @HelpOfTheGods @Wolverine32 @omgitsjc
anonymous
  • anonymous
The first expression on the left just requires you to combine the like terms on the inside of the parentheses.
anonymous
  • anonymous
That would be\[4x + 2y +x - y = (4+1)x + (2-1)y = 5x + y\]
anonymous
  • anonymous
so th answer is B
anonymous
  • anonymous
Correct.
anonymous
  • anonymous
Yay! can you help with another?
anonymous
  • anonymous
Sure
anonymous
  • anonymous
What is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2? 13.4 16.4 19.4 28.4
anonymous
  • anonymous
|dw:1435178251784:dw|
anonymous
  • anonymous
Is this the expression? \[\frac{ 1 }{ 3x^3 + 5.2y }\]
anonymous
  • anonymous
Oh ok
anonymous
  • anonymous
Well, you just need to plug in those values of x and y.
anonymous
  • anonymous
?
anonymous
  • anonymous
\[\frac{ 1 }{ 3 } \times 3^3 = 3^2 = 9\]
anonymous
  • anonymous
That's the first term. Then you need to compute\[5.2 y = 5.2 \times 2 = 10.4\]
anonymous
  • anonymous
Add those two terms up, to get your sum.
anonymous
  • anonymous
\[1/3x^3 + 5.2y\]
anonymous
  • anonymous
thats teh equation its not 1/3 times 3^3
anonymous
  • anonymous
Oh is it \[\frac{ 1 }{ 3x^3 }\] ?
anonymous
  • anonymous
yes
anonymous
  • anonymous
\[\frac{ 1 }{ 3 }x^3 + 5.2y\]
anonymous
  • anonymous
if x = 3 and y=2 what is te answer?
anonymous
  • anonymous
Ok if the expression is \[\frac{ 1 }{ 3 } 3^3 + 5.2 \times 2 = \]
anonymous
  • anonymous
Then its, 9 + 10.4 = 19.4
anonymous
  • anonymous
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