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anonymous
 one year ago
f(x) g(x)
anonymous
 one year ago
f(x) g(x)

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marinos
 one year ago
Best ResponseYou've already chosen the best response.0Do you mean the following functions ? \[f(x)=4\left( x6 \right)^{2}+3\] and \[g(x)=2\cos \left( 2x\pi \right)+4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The maximum of cosine is 1, then g max is 2+4=2 The the vertex of the flipped parabola is when is 0, cause it's negative otherwise. So f max is 0+3 =3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you explain how @Ahmadnedal

marinos
 one year ago
Best ResponseYou've already chosen the best response.0Remember that a square is always nonnegative and that the absolute value of (sine and) cosine function(s) is at most 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But the thing is, these two values are not satisfied at the same x coordinate, I think you will now be needing calculus 1 to find that point where x gets you the maximum

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is your grade right now @jacey.stewart ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You use equation x=b/2a to find the maximum Im just confused on the cosine part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The maximum of any sinsouidal function (since, cosx) is 1, therefore the maximum of cosine is 2

marinos
 one year ago
Best ResponseYou've already chosen the best response.0We have that \[\left( x6 \right)^{2}\ge0\] since it is a square. Therefore \[4\left( x6 \right)^{2}\le0\] so \[f(x)=4\left( x6 \right)^{2}+3\le3\] implying that the maximum value of the function \[f(x)\] is 3. Can you argue similarly for the other function ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In my opinion, I think the question is not well written. Again if the maximum of f and g are achieved in two different x coordinates. Thus you cannot determine which point gives you the maximum MULTIPLE OF F(X) AND G(X)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I repeat, you may need deffrentiation to find the maximum of f times g

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is what I'm saying make sense jacy?

marinos
 one year ago
Best ResponseYou've already chosen the best response.0@Ahmadnedal No differentiation is needed for these functions. There maximum value can be obtained using inqualities.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think it ultimately asked for the maximum of the multiple of F and G, isn't she?

marinos
 one year ago
Best ResponseYou've already chosen the best response.0Since \[\cos \left( 2x\pi \right)\le1\] we have \[2\cos \left( 2x\pi \right)\le2\] so \[g(x)=2\cos \left( 2x\pi \right)+4\le2+4=6\] therefore the maximum value of this function is 6, and it is the greatest of the maximum values of the two initial functions.

marinos
 one year ago
Best ResponseYou've already chosen the best response.0@Ahmadnedal I didn't see any reference to the product of f(x) and g(x) (in which case you do need differentiation to find the max value)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then you are right, it will be kinda trevial if considered two separate questions Thanksfor clarification
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