anonymous
  • anonymous
As shown below, an observer (O) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle of elevation from his line of sight. What equation and trigonometric function can be used to solve for the height (h) of the kite? What is the height of the kite? You must show all work and calculations to receive full credit.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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anonymous
  • anonymous
MrNood
  • MrNood
if oyu look at angle O - how would you name the side h with respect to O would it be Opposite Adjacent or Hypotenuse? how would you name the side 400 with respect to O would it be Opposite Adjacent or Hypotenuse?
anonymous
  • anonymous
is it adjacent @MrNood

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MrNood
  • MrNood
look at the diagram is h opposite or adjacent to O
anonymous
  • anonymous
so is o an angle? h is like a side, so I'm guessing it can't be opposites like they're not opposite angles so I'm gonna go w adjacent
anonymous
  • anonymous
@MrNood
MrNood
  • MrNood
OK you are evidently studying triangles and the functions sin cos and tan you need to be able to identify the sides of a triangle opposite, adjacent and hypotenuse, with respect to a given angle. This is a basic requirement of doing these functions. Go back to your text or notes and find out how ot identify the sides THEN come back to this question
anonymous
  • anonymous
okay nvm i know this!! don't leave me now i need help w this question.. ):
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
so h is opposite
anonymous
  • anonymous
@MrNood
MrNood
  • MrNood
ok and the 400 side is?
anonymous
  • anonymous
adjacent
MrNood
  • MrNood
OK GOOD So which of the 3 functions uses opposite and adjacent? and what is the formula using them?
anonymous
  • anonymous
tangent = opposite/adjacent
MrNood
  • MrNood
ok so write an equation with tan29 h 400 in it
anonymous
  • anonymous
@MrNood ok mister
anonymous
  • anonymous
tan29=h/400
anonymous
  • anonymous
totally misread your reply i thought you said "so I'm gonna write an equation.." sorry for taking so long
MrNood
  • MrNood
excellent so use your calculator to work out h
anonymous
  • anonymous
i keep getting a really big number i don't think its correct @MrNood
MrNood
  • MrNood
so you were correct tan29 = h/400 so multiply each side by 400 what is tan(29)?
anonymous
  • anonymous
0.88 is what i got for tan29
anonymous
  • anonymous
idk that sounds off
MrNood
  • MrNood
OK - you have made a mistake with your calculator We have 29 degrees your calculator is set to 'radians' mode
anonymous
  • anonymous
yes!
anonymous
  • anonymous
MrNood
  • MrNood
you need to find tan 29 deg
anonymous
  • anonymous
0.55
anonymous
  • anonymous
is that right
MrNood
  • MrNood
so your equation is now 0.55 = h/400 so what is h?
anonymous
  • anonymous
yay!! ok its gonna come out to h=220
MrNood
  • MrNood
OK - well done but you rounded to 0.55 is that accurate enough?
anonymous
  • anonymous
thats fine! thank you very much!
MrNood
  • MrNood
So - you started out hoping for th eanswer, and maybe thinking oyu didn't know how to do it but you DID the work!
anonymous
  • anonymous
oh no i wanted to learn how to work it out! Its no fun when its just the answer <:
anonymous
  • anonymous
thanks for helping me w that, I'm like terrible at remembering things like i read the question and i was like omg what is this even I know how to do this is just needed a little remembering (:

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