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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\(\large \color{black}{\begin{align}& \normalsize \text{which of the following is an odd function}\hspace{.33em}\\~\\ & a.)\ 2^{-x\cdot x} \hspace{.33em}\\~\\ & b.)\ 2^{x-x\cdot x\cdot x\cdot x} \hspace{.33em}\\~\\ & c.)\ \normalsize \text{both a.) and b.) } \hspace{.33em}\\~\\ & d.)\ \normalsize \text{neither a.) nor b.) } \hspace{.33em}\\~\\ \end{align}}\)
D
I got it, it's always D :P

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Other answers:

is b.) odd
I think the question could better have been which one is even
Whenever you u see an exponent, how can the minus sign get down to the 2, how can it change sign and go from positive to NEGATIVE and vice versa,, it's always positive or negative
But never both
thnx
Wlc
\[f(x)=2^{-x^2}~~\implies~~f(-x)=2^{-(-x)^2}=2^{-x^2}=f(x)\] \[g(x)=2^{x-x^4}~~\implies~~g(-x)=2^{-x-(-x)^4}=2^{-x-x^4}\]

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