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anonymous

  • one year ago

What is the area of the parallelogram? 48 cm2 48 cm2 24 cm2 24 cm2 https://lh3.googleusercontent.com/KAyzQd235G4F1gU997iCLiIhM-ZUstI2eWXZmnxHUzOvzWXnfqJ_4VhX0i6_eBBIjcmjjg=s36

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  1. sdfgsdfgs
    • one year ago
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    Cannot read the attached pic - too small! in any case, area of a parallelogram = base x height

  2. anonymous
    • one year ago
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    |dw:1435183665175:dw|

  3. anonymous
    • one year ago
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    sorry so sloppy

  4. sdfgsdfgs
    • one year ago
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    No prob :) So, the base is 8 n u need to figure out the height...any idea? |dw:1435183740250:dw|

  5. anonymous
    • one year ago
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    48\[\sqrt{3}^2, 48cm^2,2\sqrt{3}^2,or 24cm^2\]

  6. anonymous
    • one year ago
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    Sorry , 48\[48\sqrt{3}cm^2, 48cm^2, 24\sqrt{3}cm^2, 24cm^2\]

  7. sdfgsdfgs
    • one year ago
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    its alright....any idea on how to get the height? hint: tan(60deg.)=SQRT(3)

  8. anonymous
    • one year ago
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    I don't know how to figure that out

  9. sdfgsdfgs
    • one year ago
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    u know the trig function, tan?

  10. anonymous
    • one year ago
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    a little

  11. anonymous
    • one year ago
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    so is it \[48\sqrt{3}^2\]

  12. sdfgsdfgs
    • one year ago
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    wat is tan(60) equal to in the triangle that I added to ur picture?

  13. sdfgsdfgs
    • one year ago
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    sorry - tan is not the right function to use here! we need to use sin function instead. sin(60) = SQRT(3) / 2

  14. anonymous
    • one year ago
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    I don't remember what I am suppose to do. I need to know because I have a final I need to do later

  15. anonymous
    • one year ago
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    I am trying to review now

  16. sdfgsdfgs
    • one year ago
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    |dw:1435184469138:dw|

  17. anonymous
    • one year ago
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    so how do I figure out what the height is?

  18. sdfgsdfgs
    • one year ago
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    compare the triangle i drew above n the one in ur drawing...also use this: sin(60) = SQRT(3) / 2

  19. anonymous
    • one year ago
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    I'm lost!!!

  20. sdfgsdfgs
    • one year ago
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    |dw:1435184919607:dw| relax n look again plz? :)

  21. anonymous
    • one year ago
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    ok triangle is a 30/60/90

  22. anonymous
    • one year ago
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    right angle

  23. sdfgsdfgs
    • one year ago
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    u are given one side at 6 n need to find the height there so....

  24. anonymous
    • one year ago
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    they hypotenuse is 6

  25. sdfgsdfgs
    • one year ago
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    @moyer correct! :)

  26. anonymous
    • one year ago
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    base would be 3?

  27. anonymous
    • one year ago
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    height of 9?

  28. sdfgsdfgs
    • one year ago
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    |dw:1435185155669:dw| no and no for base and height....look again plz?

  29. anonymous
    • one year ago
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    yes I got that the base is 8 I just meant for the triangle it self.

  30. anonymous
    • one year ago
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    you take bh to get the answer but first I need to figure out the height of the figure, correct?

  31. sdfgsdfgs
    • one year ago
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    correct n u use the triangle n sin function to figure out h :)

  32. anonymous
    • one year ago
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    so can you explain that step

  33. sdfgsdfgs
    • one year ago
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    "triangle and sin function" are the hints...

  34. sdfgsdfgs
    • one year ago
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    |dw:1435186137448:dw| and the one here

  35. sdfgsdfgs
    • one year ago
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    |dw:1435186192280:dw|

  36. anonymous
    • one year ago
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    I don't get it I'm going to see if I can find a video on khan Academy

  37. sdfgsdfgs
    • one year ago
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    @moyer OK when u come back, apply sin(60) = SQRT(3) / 2 and u will get the ans. Good luck!

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