## anonymous one year ago What is the area of the parallelogram? 48 cm2 48 cm2 24 cm2 24 cm2 https://lh3.googleusercontent.com/KAyzQd235G4F1gU997iCLiIhM-ZUstI2eWXZmnxHUzOvzWXnfqJ_4VhX0i6_eBBIjcmjjg=s36

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1. sdfgsdfgs

Cannot read the attached pic - too small! in any case, area of a parallelogram = base x height

2. anonymous

|dw:1435183665175:dw|

3. anonymous

sorry so sloppy

4. sdfgsdfgs

No prob :) So, the base is 8 n u need to figure out the height...any idea? |dw:1435183740250:dw|

5. anonymous

48$\sqrt{3}^2, 48cm^2,2\sqrt{3}^2,or 24cm^2$

6. anonymous

Sorry , 48$48\sqrt{3}cm^2, 48cm^2, 24\sqrt{3}cm^2, 24cm^2$

7. sdfgsdfgs

its alright....any idea on how to get the height? hint: tan(60deg.)=SQRT(3)

8. anonymous

I don't know how to figure that out

9. sdfgsdfgs

u know the trig function, tan?

10. anonymous

a little

11. anonymous

so is it $48\sqrt{3}^2$

12. sdfgsdfgs

wat is tan(60) equal to in the triangle that I added to ur picture?

13. sdfgsdfgs

sorry - tan is not the right function to use here! we need to use sin function instead. sin(60) = SQRT(3) / 2

14. anonymous

I don't remember what I am suppose to do. I need to know because I have a final I need to do later

15. anonymous

I am trying to review now

16. sdfgsdfgs

|dw:1435184469138:dw|

17. anonymous

so how do I figure out what the height is?

18. sdfgsdfgs

compare the triangle i drew above n the one in ur drawing...also use this: sin(60) = SQRT(3) / 2

19. anonymous

I'm lost!!!

20. sdfgsdfgs

|dw:1435184919607:dw| relax n look again plz? :)

21. anonymous

ok triangle is a 30/60/90

22. anonymous

right angle

23. sdfgsdfgs

u are given one side at 6 n need to find the height there so....

24. anonymous

they hypotenuse is 6

25. sdfgsdfgs

@moyer correct! :)

26. anonymous

base would be 3?

27. anonymous

height of 9?

28. sdfgsdfgs

|dw:1435185155669:dw| no and no for base and height....look again plz?

29. anonymous

yes I got that the base is 8 I just meant for the triangle it self.

30. anonymous

you take bh to get the answer but first I need to figure out the height of the figure, correct?

31. sdfgsdfgs

correct n u use the triangle n sin function to figure out h :)

32. anonymous

so can you explain that step

33. sdfgsdfgs

"triangle and sin function" are the hints...

34. sdfgsdfgs

|dw:1435186137448:dw| and the one here

35. sdfgsdfgs

|dw:1435186192280:dw|

36. anonymous

I don't get it I'm going to see if I can find a video on khan Academy

37. sdfgsdfgs

@moyer OK when u come back, apply sin(60) = SQRT(3) / 2 and u will get the ans. Good luck!