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anonymous

  • one year ago

Convert (-5, pi/4) to rectangular coordinates. A. (sqrt(2) / 2, sqrt(2) / 2) B. (5 sqrt(3) / 2, 5/ 2) C. (5 sqrt(2) / 2, 5 sqrt(2) / 2) D. (-5 sqrt(2) / 2, -5 sqrt(2) / 2)

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  1. anonymous
    • one year ago
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    I am thinking that it would be B. However I am having trouble understanding how to get my answer.

  2. anonymous
    • one year ago
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    \[x = rcos \theta\]\[y= rsin \theta\]

  3. anonymous
    • one year ago
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    \[x = (-5)\cos(\frac{ \pi }{ 4 })\]\[y = (-5)\sin(\frac{ \pi }{ 4 })\]

  4. anonymous
    • one year ago
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    I don't get any of the answers :(

  5. anonymous
    • one year ago
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    yes. last step is to use a unit circle to get sin (π/4) and cos (π/4)

  6. anonymous
    • one year ago
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    45?

  7. anonymous
    • one year ago
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    Oh sin and cos of 45?

  8. anonymous
    • one year ago
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    yes

  9. anonymous
    • one year ago
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    It would be A?

  10. anonymous
    • one year ago
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    D. A doesn't have -5 for r

  11. anonymous
    • one year ago
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    Oh you just said the answer didn't you

  12. anonymous
    • one year ago
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    yes r can be negative. |dw:1435189073642:dw|

  13. anonymous
    • one year ago
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    Oh I see now! D is the answer! Thank you for your time

  14. anonymous
    • one year ago
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    no problem. you're welcome

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