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Critical numbers are where the derivative is 0 or doesn't exist. Did you find the derivative?

Ohh okay got it! I was a little confused on what it was xD

ok

Wait so the derivative is \[3x^2 - e^x\] right?

\[3x^2-e ^{-x}\]

hmm okay! thanks :)

I think I'm doing this completely wrong lol... I misunderstood the question!

Approximate a critical number of y = x^3 + e^−x using Newton’s method

That's the question

|dw:1435192671369:dw|
Then keep going until the numbers don't change much

Ohh So the same process is just repeated over an over?

and*

|dw:1435192838109:dw|
wrong equation. Thanks to @jim_thompson5910 for pointing it out

Ahh I see

What is this equation called?

Newton's method

Ohh so every time I have to use newton's method I just apply this?

Oh I understand! Thanks so much!

no problem