medal What is an equation of the line, in point-slope form, that passes through the given points and has the given slope? pont:(8,-8);slope:3 y-8=3(x+8) y+8=3(x+8) y-8=3(x-8) y+8=3(x-8)

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medal What is an equation of the line, in point-slope form, that passes through the given points and has the given slope? pont:(8,-8);slope:3 y-8=3(x+8) y+8=3(x+8) y-8=3(x-8) y+8=3(x-8)

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this one easier than the last, since they gave you the slope to being with
\[y-y_1=m(x-x_1)\] with \[x_1=8,y_1=-8\] remember the sign comes with the number
you got it yet?

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Other answers:

ok so a is the answer
no are you getting the x's confused with the y's?
i think so
i can see it is a bit confusing because they use the point \((8,-8)\) plug in \(x\) for \(x_1\) and \(-8\) for \(y_1\) in \[y-y_1=m(x-x_1)\]
oops i meant "plug in \(8\) for \(x\)"
remember that x comes before y in the alphabet, just like it does in \((x,y)\) course you have to sing that whole song until the end
ok im los t
ok lets go slow
the "point slope" formula for a line, with slope \(m\) and point \((x_1,y_1)\) is \[\huge y-y_1=m(x-x_1)\]
\(x\) and \(y\) are variables, they stay in the answer \(x_1\) and \(y_1\) are numbers
you have in this case \[x_1=8,y_1=-8,m=3\] so we plug them directly in to the formula, remembering that the minus sign that is in front of the number stays there
i will plug them directly in :\[y-(-8)=3(x-8)\]
then you see that \(-(-8)=+8\) so in the end you get \[y+8=3(x-8)\]
now i see thanks

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