anonymous
  • anonymous
Two equations are shown: • Equation 1: 3/4(x−12)=12 •Equation 2: 3/4y−12=12 Solve each equation. Then, enter a number in each box to make this statement true. The value of x is: The value of y is:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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geerky42
  • geerky42
\[\dfrac34(x-12)=12\] We need to isolate x. Any idea what to do with \(\dfrac34\)?
anonymous
  • anonymous
convert it to a decimal?
geerky42
  • geerky42
Sure. Then we have \(.75(x-12) = 12\) We still need to get rid of .75

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geerky42
  • geerky42
Maybe do something to both sides to cancel .75 out?
anonymous
  • anonymous
subtract .75 from .75 and 12?
geerky42
  • geerky42
I would go with dividing.
geerky42
  • geerky42
\(\dfrac{.75(x-12)}{.75} = \dfrac{12}{.75}\) \(\dfrac{\cancel{.75}(x-12)}{\cancel{.75}} = \dfrac{12}{.75}\) \(x-12 = \dfrac{12}{.75}\)
anonymous
  • anonymous
okk
geerky42
  • geerky42
Do you understand what is going on?
anonymous
  • anonymous
yes so 12 divided by .75 is 16?
anonymous
  • anonymous
so then 12/.75 is equal; to 9, |dw:1435197556041:dw|
anonymous
  • anonymous
okk so x=28? 28-12=16 witch is 16=16? right
anonymous
  • anonymous
yes that right :)
anonymous
  • anonymous
yay thank u guys!!!!! :-)
anonymous
  • anonymous
now equation 2 I need help also
anonymous
  • anonymous
do I do the same thing as I did the first time?
anonymous
  • anonymous
no its then 3/4Y-12 = 12 you add 12 to both sides and its 3/4Y = 24 you divide btoh sides by 3/4 and its Y = 32
anonymous
  • anonymous
its a lot to chew so if you get stuck ill help you with each part
anonymous
  • anonymous
yea I'm a little confused can u explain please
anonymous
  • anonymous
|dw:1435198260900:dw|
anonymous
  • anonymous
|dw:1435198422351:dw|
anonymous
  • anonymous
|dw:1435198514780:dw|
anonymous
  • anonymous
its not addition its multiplication so its (.75*Y) - 12 = 12
anonymous
  • anonymous
but u said add 12 to both sides
anonymous
  • anonymous
i really like using fractions but ill convert it to decimals lets start over just forget what i said
anonymous
  • anonymous
okk
anonymous
  • anonymous
|dw:1435198918158:dw|
anonymous
  • anonymous
okk thank u
anonymous
  • anonymous
i really hope i helped, sorry if i confused you
anonymous
  • anonymous
no no I understand thank u
anonymous
  • anonymous
@kenzylee

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