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anonymous

  • one year ago

Use the following scenario to answer the question: A bag contains 5 green marbles, 4 red marbles, 7 blue marbles, and 9 yellow marbles. If 3 marbles are drawn from the bag one at a time and not replaced, what is the probability of drawing a blue, yellow, and red marble in that particular order? Select one: a. equation b. equation c. equation d. equation

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  1. kropot72
    • one year ago
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    There are 25 marbles in the bag. The probability of drawing a blue marble first is 7/25. Having drawn a blue marble there are 24 marbles left, and the probability of drawing a yellow marble second is 9/24. Now there are 23 marbles and the probability of drawing a red marble next is 4/23. The required probability is therefore the product of the three values of probability: \[\large P(blue,\ yellow,\ red)=\frac{7\times9\times4}{25\times24\times23}\]

  2. anonymous
    • one year ago
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    a. 1/48 b. 5/18 c. 21/1150 d. 6/11 these are fraction i just cant write them like fractions

  3. kropot72
    • one year ago
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    The result that I gave you can be simplified to give one of the choices. Can you try to simplify.

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