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anonymous

  • one year ago

Will fan and medal. Find the value of x in the logarithm log2 x = -3. A. 1/3 B. 3/2 C. 1/8 D. 8

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  1. UnkleRhaukus
    • one year ago
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    \[\log_2(x)=3\] Apply the log identity \[\log_b(x) = y \iff x= b^y\]

  2. anonymous
    • one year ago
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    Could you please just walk me through the steps because I really don;t know what I'm doing.

  3. UnkleRhaukus
    • one year ago
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    don't forget the minus sign *\(\log_2(x)=-3\)

  4. UnkleRhaukus
    • one year ago
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    there only is two steps, the first is to apply the log identity

  5. UnkleRhaukus
    • one year ago
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    \[\log_2(x)=-3\] raising both sides of the equation to the base of the logarithm... \[2^{\log_2(x)}=2^{-3}\] the left hand side simplifies \[x=2^{-3}\]

  6. UnkleRhaukus
    • one year ago
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    now jus simplify the right hand side

  7. anonymous
    • one year ago
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    would it be 1/8?

  8. UnkleRhaukus
    • one year ago
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    yep

  9. anonymous
    • one year ago
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    Thank you!

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