anonymous one year ago Find the vertex, focus, directrix, and focal width of the parabola. -(1/16)x^2 = y

1. misssunshinexxoxo

x^2=−16y

2. misssunshinexxoxo

Plug in (y - k) = a (x - h)^2 and gives solution :)

3. perl

You can use the equation $$\Large y= \frac{1}{4p} (x-h)^2 +k$$The distance from the origin $$(h,k)$$ to the focus is $$|p |$$

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