anonymous
  • anonymous
Solve for x. -ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@nincompoop
dan815
  • dan815
okay so if you were to subtract the same quantitity from both sides the inequality still holds
dan815
  • dan815
for example| say we have 5>4 which is true if we subtract 2 from both sides 5-2>4-2 we just shifted the numbers down by 2 3>2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

dan815
  • dan815
same thing with multiplication
dan815
  • dan815
suppose a > b then 3a>3b is still true
dan815
  • dan815
|dw:1435216228375:dw|
anonymous
  • anonymous
subtract 3 from each side?
anonymous
  • anonymous
nvm
dan815
  • dan815
the final rule you need to know is
dan815
  • dan815
multiplication by -1 or any negative number, here is where the inequality flips
dan815
  • dan815
if a > b then -a < -b
dan815
  • dan815
this can be seen more clearly with number line examples
dan815
  • dan815
|dw:1435216365389:dw|
dan815
  • dan815
|dw:1435216407582:dw|
dan815
  • dan815
the distance from the 0 is the same, however now a is MORE negative and b is LESS negative
dan815
  • dan815
so -a<-b and a>b
dan815
  • dan815
ill leave you with an excercise show this is still true, when a is negative and b is positive to start with
dan815
  • dan815
lool
dan815
  • dan815
that guy called us nerds and left
dan815
  • dan815
arent u enraged
Astrophysics
  • Astrophysics
lol
Astrophysics
  • Astrophysics
slow down dan
anonymous
  • anonymous
im just so confused
Astrophysics
  • Astrophysics
thats what dan does he throws bunch of info at you and expects you to get it, he's a noobie, im the hero I'll save you
Astrophysics
  • Astrophysics
lolol
dan815
  • dan815
make sure u read all that over! after astros help
dan815
  • dan815
its important, please do it
anonymous
  • anonymous
you lost me at "if a > b then -a < -b"
dan815
  • dan815
imagine the number line,
anonymous
  • anonymous
yeah that number line got me confused lol
Astrophysics
  • Astrophysics
I think you should do the algebra first and then you can figure it out
Astrophysics
  • Astrophysics
Dan gave lots of good info, but he's a hyper one and a smart one :P, so lets take it down a bit.
anonymous
  • anonymous
please lol
Astrophysics
  • Astrophysics
|dw:1435216787284:dw| so this is what we're given right and we need to solve for x, so a rule I'll say right now, when we do algebra with inequalities, if we multiply OR divide by a negative number the sign of the inequality flips ok?
anonymous
  • anonymous
ok
Astrophysics
  • Astrophysics
Great, so lets start off and do our algebra, any idea what we can do with 3b?
anonymous
  • anonymous
divide it with 3?
Astrophysics
  • Astrophysics
Well, we want to move everything but the x on the left side, meaning we isolate x/ solving x. So to do this an easy way to look at it is, do the opposite of what operation already exists, so notice we have +3b to cancel it out (we want 0 3b's on the left) we would subtract it, as follow: |dw:1435217000808:dw| and remember what we do to one side we MUST also do it to the other.
Astrophysics
  • Astrophysics
That should say to the right side sorry* :P
Astrophysics
  • Astrophysics
|dw:1435217056160:dw| so now we have this, let me know when you're ready to move on
anonymous
  • anonymous
ok got it
Astrophysics
  • Astrophysics
Alright cool, so what should we do next, remember we want to keep x there, but not the -a, but we can't have -a be 0 otherwise x will be 0 to and it would make no sense!
Astrophysics
  • Astrophysics
What operation do you think would be best :)
anonymous
  • anonymous
get rid of the -a by adding a?
Astrophysics
  • Astrophysics
Nice try, but notice it's "attached" to the x, that means it's being multiplied, so we divide by -a on both sides!
Astrophysics
  • Astrophysics
Also remember the little rule I mentioned earlier, what happens if we divide by a negative sign?
anonymous
  • anonymous
it becomes a positive?
Astrophysics
  • Astrophysics
I mean to the inequality
Astrophysics
  • Astrophysics
|dw:1435217372626:dw| remember the sign flips
anonymous
  • anonymous
oh yeah my bad
Astrophysics
  • Astrophysics
|dw:1435217417366:dw| now we can put it in words, I will let you figure that out!
Astrophysics
  • Astrophysics
But everything so far makes sense right?
anonymous
  • anonymous
so far yes
Astrophysics
  • Astrophysics
Ok so try comparing it with one of your options and see if you can get it
Astrophysics
  • Astrophysics
Or you can leave the answer as |dw:1435217588112:dw|
anonymous
  • anonymous
option A?
Astrophysics
  • Astrophysics
Mhm, is it x< or is it x>
Astrophysics
  • Astrophysics
You be able to eliminate two answers right away
anonymous
  • anonymous
>
Astrophysics
  • Astrophysics
Lol just look at the answer
Astrophysics
  • Astrophysics
It's right there!
anonymous
  • anonymous
it doesnt show the same answer for the options
Astrophysics
  • Astrophysics
|dw:1435217852979:dw|
anonymous
  • anonymous
doesnt show the same answer
anonymous
  • anonymous
3b+5/a?
Astrophysics
  • Astrophysics
\(\color{blue}{\text{Originally Posted by}}\) @CatalystDuzIt Solve for x. -ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a \(\color{blue}{\text{End of Quote}}\) We can eliminate the first one and the second option, so look at three and four.
Astrophysics
  • Astrophysics
I think this will make it clear |dw:1435217982712:dw|
Astrophysics
  • Astrophysics
|dw:1435218006866:dw|
anonymous
  • anonymous
yeah thats it
anonymous
  • anonymous
thanks man. i appreciate it!
Astrophysics
  • Astrophysics
No worries, the answers they gave you are in a way you would never put...so yeah haha.

Looking for something else?

Not the answer you are looking for? Search for more explanations.