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anonymous
 one year ago
Solve for x.
ax + 3b > 5
x > the quantity 3 times b minus 5 all over negative a
x > the quantity 5 minus 3 times b all over negative a
x < the quantity 3 times b plus 5 all over negative a
x < the quantity negative 3 times b plus 5 all over negative a
anonymous
 one year ago
Solve for x. ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a

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dan815
 one year ago
Best ResponseYou've already chosen the best response.1okay so if you were to subtract the same quantitity from both sides the inequality still holds

dan815
 one year ago
Best ResponseYou've already chosen the best response.1for example say we have 5>4 which is true if we subtract 2 from both sides 52>42 we just shifted the numbers down by 2 3>2

dan815
 one year ago
Best ResponseYou've already chosen the best response.1same thing with multiplication

dan815
 one year ago
Best ResponseYou've already chosen the best response.1suppose a > b then 3a>3b is still true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0subtract 3 from each side?

dan815
 one year ago
Best ResponseYou've already chosen the best response.1the final rule you need to know is

dan815
 one year ago
Best ResponseYou've already chosen the best response.1multiplication by 1 or any negative number, here is where the inequality flips

dan815
 one year ago
Best ResponseYou've already chosen the best response.1this can be seen more clearly with number line examples

dan815
 one year ago
Best ResponseYou've already chosen the best response.1the distance from the 0 is the same, however now a is MORE negative and b is LESS negative

dan815
 one year ago
Best ResponseYou've already chosen the best response.1ill leave you with an excercise show this is still true, when a is negative and b is positive to start with

dan815
 one year ago
Best ResponseYou've already chosen the best response.1that guy called us nerds and left

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2thats what dan does he throws bunch of info at you and expects you to get it, he's a noobie, im the hero I'll save you

dan815
 one year ago
Best ResponseYou've already chosen the best response.1make sure u read all that over! after astros help

dan815
 one year ago
Best ResponseYou've already chosen the best response.1its important, please do it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you lost me at "if a > b then a < b"

dan815
 one year ago
Best ResponseYou've already chosen the best response.1imagine the number line,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah that number line got me confused lol

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I think you should do the algebra first and then you can figure it out

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Dan gave lots of good info, but he's a hyper one and a smart one :P, so lets take it down a bit.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1435216787284:dw so this is what we're given right and we need to solve for x, so a rule I'll say right now, when we do algebra with inequalities, if we multiply OR divide by a negative number the sign of the inequality flips ok?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Great, so lets start off and do our algebra, any idea what we can do with 3b?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Well, we want to move everything but the x on the left side, meaning we isolate x/ solving x. So to do this an easy way to look at it is, do the opposite of what operation already exists, so notice we have +3b to cancel it out (we want 0 3b's on the left) we would subtract it, as follow: dw:1435217000808:dw and remember what we do to one side we MUST also do it to the other.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2That should say to the right side sorry* :P

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1435217056160:dw so now we have this, let me know when you're ready to move on

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Alright cool, so what should we do next, remember we want to keep x there, but not the a, but we can't have a be 0 otherwise x will be 0 to and it would make no sense!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2What operation do you think would be best :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0get rid of the a by adding a?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Nice try, but notice it's "attached" to the x, that means it's being multiplied, so we divide by a on both sides!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Also remember the little rule I mentioned earlier, what happens if we divide by a negative sign?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it becomes a positive?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I mean to the inequality

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1435217372626:dw remember the sign flips

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1435217417366:dw now we can put it in words, I will let you figure that out!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2But everything so far makes sense right?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Ok so try comparing it with one of your options and see if you can get it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Or you can leave the answer as dw:1435217588112:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Mhm, is it x< or is it x>

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You be able to eliminate two answers right away

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Lol just look at the answer

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2It's right there!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it doesnt show the same answer for the options

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1435217852979:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0doesnt show the same answer

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @CatalystDuzIt Solve for x. ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a \(\color{blue}{\text{End of Quote}}\) We can eliminate the first one and the second option, so look at three and four.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I think this will make it clear dw:1435217982712:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1435218006866:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks man. i appreciate it!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2No worries, the answers they gave you are in a way you would never put...so yeah haha.
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