Please help me.. I'm really confused. /:

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Please help me.. I'm really confused. /:

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I've already got part A... A = 9(x+23)/2 2A = 9(x+23) 2A/9 = (x+23) 2A/9 - 23 = x x = 2A/9 - 23
But I need help on the other 2.
ok so take the equation that is had from part a, and instead of the variable, substitute it 108 then solve, u get it now?

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Other answers:

so plug 108 for a
the solve for x
ok just a sec
u need help?
the equation is x=2a/9-23 so 2x108=216 216/9=24 24-23=1 x=1
So is it this? 108 = 9/2(x+23) 108 = 9(x+23)/2 216 = 9(x+23) 216/9 = x + 23 24 = x+23 24 - 23 = x 1 = x x = 1
yes great!
u need help on part c?
Yay! (: Yea, if you don't mind.
ok for part c
ok so we need to solve for n, this means we need to set an equation that solves for n so what we need to do is isolate the variable "n" so your steps are
–np – 90 > 30 first add 90 to both sides -np>120 then you want to divide by p -n>120/p then finally u have to divide by -1 since there is an invisible 1 next to the p and we need to get rid of that negative n>-120/p is your final answer!
I was taught that if you divided by a negative, the sign was flipped. Am I confused about that?
yes whenever u divide anything my a negative it becomes the oposite sign, youre correc about that!
by*
So should the sign be flipped at the end in this?
yes the answer is a negative fraction which is -120/p
Oh ok. Thank you so much for the help! (:
np, wheneever u have a question, just tag me! id love to help
Thanks, I will if i need help.

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