kmullis6
  • kmullis6
Please help me.. I'm really confused. /:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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kmullis6
  • kmullis6
I've already got part A... A = 9(x+23)/2 2A = 9(x+23) 2A/9 = (x+23) 2A/9 - 23 = x x = 2A/9 - 23
kmullis6
  • kmullis6
But I need help on the other 2.
anonymous
  • anonymous
ok so take the equation that is had from part a, and instead of the variable, substitute it 108 then solve, u get it now?

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anonymous
  • anonymous
so plug 108 for a
anonymous
  • anonymous
the solve for x
kmullis6
  • kmullis6
ok just a sec
anonymous
  • anonymous
u need help?
anonymous
  • anonymous
the equation is x=2a/9-23 so 2x108=216 216/9=24 24-23=1 x=1
kmullis6
  • kmullis6
So is it this? 108 = 9/2(x+23) 108 = 9(x+23)/2 216 = 9(x+23) 216/9 = x + 23 24 = x+23 24 - 23 = x 1 = x x = 1
anonymous
  • anonymous
yes great!
anonymous
  • anonymous
u need help on part c?
kmullis6
  • kmullis6
Yay! (: Yea, if you don't mind.
anonymous
  • anonymous
ok for part c
anonymous
  • anonymous
ok so we need to solve for n, this means we need to set an equation that solves for n so what we need to do is isolate the variable "n" so your steps are
anonymous
  • anonymous
–np – 90 > 30 first add 90 to both sides -np>120 then you want to divide by p -n>120/p then finally u have to divide by -1 since there is an invisible 1 next to the p and we need to get rid of that negative n>-120/p is your final answer!
kmullis6
  • kmullis6
I was taught that if you divided by a negative, the sign was flipped. Am I confused about that?
anonymous
  • anonymous
yes whenever u divide anything my a negative it becomes the oposite sign, youre correc about that!
anonymous
  • anonymous
by*
kmullis6
  • kmullis6
So should the sign be flipped at the end in this?
anonymous
  • anonymous
yes the answer is a negative fraction which is -120/p
kmullis6
  • kmullis6
Oh ok. Thank you so much for the help! (:
anonymous
  • anonymous
np, wheneever u have a question, just tag me! id love to help
kmullis6
  • kmullis6
Thanks, I will if i need help.

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