check my answer? Find S_11 for 1 + 2 + 4 + 8 + ... I got 2047, is that correct?

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check my answer? Find S_11 for 1 + 2 + 4 + 8 + ... I got 2047, is that correct?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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wht is "S"?
I believe that it means the sum of the series
idk the answer to this

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Other answers:

Write out your equation for me.
well I know that r=2 and so I multiplied by 2 for each and got 1,2,4,8,16,32,64,128,256,512,1024 and then I looked it up because I wasn't sure what to do next and they got 2047 and I wanted to know how they got that
There is an equation. First you have to find the t11. T11 = term 11.
The eleventh term is 1024 I believe
its geometric progression, a, ar, ar^2, ar^3.... the common ratio here is 2, that is, every next term is "previous term multiplied by 2" sum in a GP is given by the formula \[ \frac{ a (1-r ^{n})}{ 1-r }\]
take a as 1, r as 2 and n as 11
(1(1-2^11))/1-2 =1-2048/1-2 =2047
So yes, your answer is 2047
okay thank you

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