anonymous
  • anonymous
Find the sum of the following infinite geometric series, if it exist. 1/2+(-1/4)+1/8+(-1/16)+...
Mathematics
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anonymous
  • anonymous
Find the sum of the following infinite geometric series, if it exist. 1/2+(-1/4)+1/8+(-1/16)+...
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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sloppycanada
  • sloppycanada
By chance do you do Keystone Online? I've seen this exact questions on their site.. First step for this - How does one go about finding the ratio for this?
anonymous
  • anonymous
the ratio is -1/2
sloppycanada
  • sloppycanada
Since it is in between 1 and -1, will it converge or not? This is very important.

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anonymous
  • anonymous
I don't think so???
sloppycanada
  • sloppycanada
No, since it does converge, we have a solution
sloppycanada
  • sloppycanada
|dw:1435222463385:dw|
anonymous
  • anonymous
how do I find a regular t
sloppycanada
  • sloppycanada
|dw:1435222584005:dw| In this case we can use "1" for the regular t.
anonymous
  • anonymous
so .5/1-2 = .5/-1 = -.5? @sloppycanada
sloppycanada
  • sloppycanada
I got something different. |dw:1435222874711:dw|
anonymous
  • anonymous
opps I put the wrong number for r. thank you <3
anonymous
  • anonymous
so if I do that I get .5/1.5 right?
sloppycanada
  • sloppycanada
I mean, that's one way of doing it... but I guess. If you have an iPad, there's a free app called Myscript calculator that's pretty helpful for this sorts of situations.

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