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So, what's the question? Are we supposed to factor it out?
Yes. @YanaSidlinskiy I need help doing that.
first take x out of the quadratic function
But one is negative and one isn't..
oh sorry you can simplify first (x^2+5x−14x^2 = 5x - 13x^2 = x(5 - 13x)
there are no common factors here are you sure you have the question right?
The 14 isn't supposed to have \(x^2\)
i suspect thet the quadratic is x^2+5x−14
Sorry about that.
to factor x^2+5x−14 you need to find 2 numbers whose product is -14 and whose sum is +5
can you tell me what those 2 numbers sre?
think of the factors of -14
Their product has to be -14 but the sum has to be 5?
Hm.. I don't really know, but I know for the -14..
-14 = -7 * 2 or -14 = -2 * 7
which 2 factors add up to +5?
right on so the factors of (x^2+5x−14) are ( x - 7)(x + 2)
if you expand this function you'll see it works out to x^2 + 5x - 14
* oops my bad its (x + 7)(x - 2)
Yes. Thank you so much.
Now you need to factor x^2 - 49
can u do that?
49 - x^2
(x-7)(x+7) ? I don't know..
49 - x^2 = (7 - x)(7 + x) so can you see the common factor?
x + 7
Oh, okay. Thanks a bunch.