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mathmath333
 one year ago
Graphical functions
mathmath333
 one year ago
Graphical functions

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align} &a.) \ f(x)=f(x) \hspace{.33em}\\~\\ &b.) \ f(x)=f(x) \hspace{.33em}\\~\\ &c.) \ \normalsize \text{neither even nor odd function} \hspace{.33em}\\~\\ &d.) \ f(x)\ \normalsize \text{doesn't exist at atleast one point of the domain.} \hspace{.33em}\\~\\ \end{align}}\) \(\large \color{black}{\begin{align} \normalsize \text{}\hspace{.33em}\\~\\ \end{align}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i guess we are missing \(f(x)\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435239903652:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0looks symmetric wrt the y axis to me, how about you?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1u mean it even function?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, if it is symmetric wrt the y axis, it is even

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1but it fails the vertical line test i think.

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.1why u think it fails ? like its not 11 function also not onto but u can see the symmetric

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435240841975:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1vertical line test verdict : failed.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3yeah the graph fails to be a function x=2, 2

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1book gave it as even gunction

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3maybe x=2, 2 are vertical asymptotes ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3thats the only way the textbook answer makes sense i guess

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.1huh dont use vertical line test its hmmm not our point the function itself is not a function but indeed its an even relation

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3then the vertical line test passes because that x=2, 2 lines don't really exist, think that the graph is defined only in the interval (2, 2)

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.1so that would be half circle

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3something like this dw:1435242199499:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1this is even funxtion

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Yes the graph that you showed must be like this to be called a "function"
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