anonymous
  • anonymous
I have a question, can anybody help me? What is the general form of the equation of the given circle with center A? http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/258cc385d685420384bc0a8b50aa8568 x2 + y2 + 6x − 24y − 25 = 0 x2 + y2 − 6x + 24y + 128 = 0 x2 + y2 + 6x – 24y + 128 = 0 x2 + y2 + 6x − 24y + 148 = 0
Geometry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
The equation of a circle with the center (h, k) and radius r is \[(x-h)^2+(y-k)^2=r^2\] Your center is (-3,12) so that's h and k. Your radius is 5. Plug in the numbers and expand the equation
anonymous
  • anonymous
(x-(-3)2 + (y-12)2 = 25 right?
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
and what do i do next ? :s
anonymous
  • anonymous
foil (x+3)² and (y-12)²
anonymous
  • anonymous
is it (x+9) + (y + 144) = 25 ??
anonymous
  • anonymous
no. you need to use FOIL for both the x and y (x + 3)² + (y - 12)² = 25 means \[(x+3)(x+3)+(y-12)(y-12)=25\]
anonymous
  • anonymous
so it would be 6x and 24y right?
anonymous
  • anonymous
6x and -24y
anonymous
  • anonymous
okay so we can take out b and c in the answers right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
is it a?
anonymous
  • anonymous
i don't know. I'm not actually working this problem. just following along to make sure your work is right. and now that I look it doesn't look like you can exclude both b and c yet
anonymous
  • anonymous
Ugh, i suck at math x.x
anonymous
  • anonymous
what did you get when you multiplied (x+3)(x+3)? you've got to show me something so I can see where you're going wrong
anonymous
  • anonymous
6x and -24y
anonymous
  • anonymous
you couldn't have gotten just 6x and -24y. Show me the whole equation
anonymous
  • anonymous
once we got that part right I can show you how to simplify it into the form they want
anonymous
  • anonymous
so this is what I got with FOIL (x-3) + (x-3) + (y-12) + (y-12) = 25
anonymous
  • anonymous
not sure if you have to multiply the 25 too..
anonymous
  • anonymous
ok. so FOIL is actually multiplication. it stands for First, Inner, Outer, Last. just to help you remember how to distribute. I'm going to show you (x - 3)(x - 3). |dw:1435246652683:dw|
anonymous
  • anonymous
ok. so FOIL is actually multiplication. it stands for First, Inner, Outer, Last. just to help you remember how to distribute. I'm going to show you (x + 3)(x + 3). |dw:1435246844411:dw|
anonymous
  • anonymous
all those - should be + because our equation was (x + 3)(x + 3)
anonymous
  • anonymous
You try with (y -12)(|dw:1435246933731:dw|y-12)
anonymous
  • anonymous
y2 - 24y + 144
anonymous
  • anonymous
right. so the equation for the circle becomes \[x^2+6x+9+y^2-24y+144=25\]
anonymous
  • anonymous
and you combine like terms right?
anonymous
  • anonymous
yes. don't forget to subtract the 25 from the right side since they want that side to be 0.
anonymous
  • anonymous
\[x ^{2} + y ^{2} -6x - 24y + 128 = 0\]
anonymous
  • anonymous
close. +6x :)
anonymous
  • anonymous
Yaaay!, omg you saved my life, thanks a lot n.n
anonymous
  • anonymous
no problem
anonymous
  • anonymous
can you help me out in another question? please ? :c

Looking for something else?

Not the answer you are looking for? Search for more explanations.