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anonymous

  • one year ago

anyone from CA with ALg 2. B

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  1. anonymous
    • one year ago
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    simplify the trignometic expression: sin^2theta/1+costheta

  2. anonymous
    • one year ago
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    1.) sin(theta)+cos(theta)cot(theta) ---- sin(x) + cos(x*(cos/sin) ---- = (sin^2(x) + cos^2(x))/sin(x) = 1/sin(x) = csc(x) ======================================================= 2.)cos^2(theta)+tan^2(theta)cos^2(theta) ---- cos^2(x) + [sin^2(x)/cos^2(x)*cos^2(x)] ---- = cos^2(x) + sin^2(x) ----- = 1

  3. anonymous
    • one year ago
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    i dont have that in my answer choices: Ill show you a. cos theta b 1 + cos theta c. 1 - cos theta d. 1 - cos theta/ cos thetta

  4. anonymous
    • one year ago
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    ok ill try and solve that

  5. anonymous
    • one year ago
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    okay thanks

  6. anonymous
    • one year ago
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    im still checking the answer but it might be A but im not positive yet so dont put that

  7. anonymous
    • one year ago
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    ok where are you checing the answer

  8. anonymous
    • one year ago
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    what type of math is this exactly

  9. anonymous
    • one year ago
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    i mean like is it trigonometry

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