anonymous
  • anonymous
If the point (1, 5) lies on a circle whose center is at the origin, what is the equation of the circle? A.) x(squared) + y(squared) = 26 B.) x(squared) + y(squared) = 16 C.) x(squared) + y(squared) = 13 D.) x(squared) + y(squared) = 11
Mathematics
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anonymous
  • anonymous
If the point (1, 5) lies on a circle whose center is at the origin, what is the equation of the circle? A.) x(squared) + y(squared) = 26 B.) x(squared) + y(squared) = 16 C.) x(squared) + y(squared) = 13 D.) x(squared) + y(squared) = 11
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
the anwer is C I THINK
anonymous
  • anonymous
The radius is the distance from the center to the circle, so use the distance formula again to find the radius. r = distance between (0,0) and (1,5)

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dumbcow
  • dumbcow
the equation for a circle actually comes directly from the distance formula
anonymous
  • anonymous
I got b, is that right?
anonymous
  • anonymous
NO ITS c
anonymous
  • anonymous
no.
dumbcow
  • dumbcow
hmmm... \[x^2 + y^2 = r^2\] (x,y) = (1,5) \[1^2 + 5^2 = 1+25=26\]
anonymous
  • anonymous
ITS CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC

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