A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
If the point (1, 5) lies on a circle whose center is at the origin, what is the equation of the circle?
A.) x(squared) + y(squared) = 26
B.) x(squared) + y(squared) = 16
C.) x(squared) + y(squared) = 13
D.) x(squared) + y(squared) = 11
anonymous
 one year ago
If the point (1, 5) lies on a circle whose center is at the origin, what is the equation of the circle? A.) x(squared) + y(squared) = 26 B.) x(squared) + y(squared) = 16 C.) x(squared) + y(squared) = 13 D.) x(squared) + y(squared) = 11

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the anwer is C I THINK

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The radius is the distance from the center to the circle, so use the distance formula again to find the radius. r = distance between (0,0) and (1,5)

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.1the equation for a circle actually comes directly from the distance formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got b, is that right?

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.1hmmm... \[x^2 + y^2 = r^2\] (x,y) = (1,5) \[1^2 + 5^2 = 1+25=26\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ITS CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.