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- anonymous

Which of the following is the equation of a circle whose center is at the origin and whose radius is 5 ?
x(squared) + y(squared) =√5
x(squared) + y(squared) = 5
x(squared) + y(squared) = 10
x(squared) + y(squared) = 25

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- anonymous

- schrodinger

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- anonymous

@peachpi I don't understand how to do this one!

- welshfella

the equation whose centre is at the origin and whose radius is r is
x^2 + y^2 = r^2

- welshfella

now substitute for r = sqrt5 and you have it

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- anonymous

I got 5

- welshfella

you got 5 for what - i think you are on the right track

- welshfella

you need the correct value for r^2

- anonymous

so then would It be √5?

- welshfella

√5? is given in the question. its the radius ( r ) of the circle.

- welshfella

so it √5 is r what is r^2?

- welshfella

* if

- welshfella

r^2 = √5 * √5 = ?

- anonymous

what does ^ mean?

- anonymous

- anonymous

10?

- welshfella

^ means 'to the power' or exponential
r^2 = r * r

- welshfella

the square root of some number times the square root of the number = the number
( by definition)
so sqrt 3 * sqrt 3 = 3

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