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anonymous

  • one year ago

Which of the following is the equation of a circle whose center is at the origin and whose radius is 5 ? x(squared) + y(squared) =√5 x(squared) + y(squared) = 5 x(squared) + y(squared) = 10 x(squared) + y(squared) = 25

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  1. anonymous
    • one year ago
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    @peachpi I don't understand how to do this one!

  2. welshfella
    • one year ago
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    the equation whose centre is at the origin and whose radius is r is x^2 + y^2 = r^2

  3. welshfella
    • one year ago
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    now substitute for r = sqrt5 and you have it

  4. anonymous
    • one year ago
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    I got 5

  5. welshfella
    • one year ago
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    you got 5 for what - i think you are on the right track

  6. welshfella
    • one year ago
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    you need the correct value for r^2

  7. anonymous
    • one year ago
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    so then would It be √5?

  8. welshfella
    • one year ago
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    √5? is given in the question. its the radius ( r ) of the circle.

  9. welshfella
    • one year ago
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    so it √5 is r what is r^2?

  10. welshfella
    • one year ago
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    * if

  11. welshfella
    • one year ago
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    r^2 = √5 * √5 = ?

  12. anonymous
    • one year ago
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    what does ^ mean?

  13. anonymous
    • one year ago
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    @welshfella

  14. anonymous
    • one year ago
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    10?

  15. welshfella
    • one year ago
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    ^ means 'to the power' or exponential r^2 = r * r

  16. welshfella
    • one year ago
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    the square root of some number times the square root of the number = the number ( by definition) so sqrt 3 * sqrt 3 = 3

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