anonymous
  • anonymous
Shanna writes the formula f(x + 1) = 2.5f(x) when f(1) = 2 to represent this sequence: 2, 5, 12.5, 31.25, … Which error did Shanna make?
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
A) She used the incorrect common ratio. B) She used the incorrect initial value. C) She should have multiplied by f(x) rather then have it as an exponent. D) She treated the sequence as geometric instead of arithmetic.
Owlcoffee
  • Owlcoffee
Well, you'll have to determine the common ratio the same way, divide the second by the first, and if it does not give 2,5 as a result, she used the wrong common ratio.
anonymous
  • anonymous
what do you think @shaylaLuv ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
B.
anonymous
  • anonymous
I think shanna did nothing wrong
anonymous
  • anonymous
\(f(x + 1) = 2.5f(x)\), \(f(1) = 2\), let \(x=1\)\[f(2)=2.5f(1)=2.5 \times 2=5\]and let \(x=2\)\[f(3)=2.5f(2)=2.5 \times5=12.5\]let \(x=3\)\[f(4)=2.5f(3)=2.5 \times 12.5=31.25\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.