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zarkam21

  • one year ago

Help, will medal =)

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  1. zarkam21
    • one year ago
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  2. anonymous
    • one year ago
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    To solve this, recall the definition of a perfect square trinomial.

  3. anonymous
    • one year ago
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    A perfect square trinomial means that the factorized form of the trinomial takes on the form of \[(x-a)^2\]

  4. anonymous
    • one year ago
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    This means that the roots of the quadratic equation must be repeated.

  5. anonymous
    • one year ago
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    Now, you just need to plug the coefficients of the given trinomial into the quadratic formula.

  6. anonymous
    • one year ago
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    \[x = \frac{-b \pm \sqrt{ b^2-4ac }}{ 2a } \]

  7. anonymous
    • one year ago
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    Notice however, that you have this plus or minus operation in the quadratic formula.

  8. anonymous
    • one year ago
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    That plus or minus operation is what normally gives you two distinct roots. But you want a repeated root. Your solution is to set the square root term to 0.

  9. zarkam21
    • one year ago
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    so the answer is 0

  10. anonymous
    • one year ago
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    No, by setting the square root term to 0, I mean:\[b^2-4ac = 0\]

  11. anonymous
    • one year ago
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    From the problem a = 1, b = -28, c = ?

  12. anonymous
    • one year ago
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    We are trying to solve for variable c.\[(-28)^2 = 4c\]

  13. anonymous
    • one year ago
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    Do you understand?

  14. zarkam21
    • one year ago
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    yes so I would just divide (-28)^2 by 4

  15. anonymous
    • one year ago
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    Correct, and that would be the constant term for your perfect square trinomial

  16. zarkam21
    • one year ago
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    196?

  17. zarkam21
    • one year ago
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    Is 196 correct

  18. anonymous
    • one year ago
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    Correct

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