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anonymous

  • one year ago

will give medal Mr. Brownwood invests a certain amount of money at 9% interest and $1,800 more than that amount in another account at 11% interest. At the end of one year, he earned a total of $818 in interest. How much money was invested in each account? A) $3,500 at 9%; $4,300 at 11% B) $3,400 at 9%; $3,200 at 11% C) $3,100 at 9%; $4,900 at 11%

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  1. kropot72
    • one year ago
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    The equation that you need to solve this is: 0.09a + 0.11(a + 1800) = 818 Where a is the amount invested a 9%.

  2. anonymous
    • one year ago
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    so would it be c ?

  3. kropot72
    • one year ago
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    Yes, C is correct.

  4. anonymous
    • one year ago
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    k thanks :)

  5. kropot72
    • one year ago
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    You're welcome :)

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