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i have no clue how to do that

this the the graph

i still dont understand

kropot you there?

can you help me find the x and y intercepts

Put y equal to zero. Then use the formula for solving any quadratic to find the two values of x.

and that is the equation for that parabola using the 3 points i said above?

i dont know how to use the quadratic formula, very well

i still have no clue how to find them

so -23 would be my y-intercept correct?

To find point C on the graph you need to find the value of the quadratic when x = 5.

and how exactly do i do that?

Yes, the intercept on the y-axis is at y = -23.

so now that i have my y-intercept how do i find my x-intercept?

Solve the quadratic
\[\large -x^{2}+10x-23=0\]
using
\[\large x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]

so the x-intercept is 2?

when i pulgged x into the equation i got y=-5^2+10(5)-23

so am i right about the x-inttercept?

but thats what i got when i plugged it into the equation

The intercepts on the x-axis are found from
\[\large x=\frac{-10\pm \sqrt{8}}{-2}\]

the answer i got is definetly not right

i got 5+-sqrt2

What is the answer then?

5?

im not sure, im really bad at math

That result checks out for me.

so its right?

Yes.

but the way that says it makes it seem like it should be points but im not sure

Try the values 3.586 and 6.414 for the intercepts on the x-axis.

and -23 for the y?

Yes.

You're welcome. Please post any more questions on OS. You can tag me if you like.

okay thank you!

If this is answered, close the question, please. :)

You're welcome :)