Help with Laws of Sines!!! Will Medal!

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Help with Laws of Sines!!! Will Medal!

Mathematics
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|dw:1435263261477:dw|
sine rule is a / sin A = b / sin b = c / sin C

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thats 200 not 20 ( in the diagram)
So we would set the equation up like:\[\sin(B) = \frac{ 200 }{ \sin(52) } \times 234?\]
to find angle B we have 234 / sin B = 200/ sin 52
cross multiply 200 sin B = 234*sin 52 sin B = (234* sin52) / 200
sin B = .9219
0.9220 to 4 dec places
Ok! So now how would we find the angles for B?
use your calculator - the key marked sin-1
Oh I completely forgot about arcsin! Thanks for reminding me. Anyway, I got 67.22 degrees! Are there going to be more than one answer or is this it?
hmmm i'll have to check if theres another answer 76.22 is correct
Great! I am not sure if there is another answer but if there is, it should be 112.8
yes hm i've forgotten this bit of trig - i dont think there is as the length of b would have to be grater than 235
Ok, so would you say there is only one answer to this problem making it B?
|dw:1435264077166:dw|
yes
It was A :( but that;s okay :) Thank you for your help!
|dw:1435264202417:dw|
yes that's right - theres the 2 possibilities in the diagram
Oh I see now! Thank you!
its call ed the ambiguous case where 2 angles are possible
I don't like these cases hahaha. Always trick me!

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