What is the rate of change of the revenue when there are 1000 downloads. So far I have R'(1000) = (130 - .019(1000))e^(-.000250(1000)). How do I calculate to get the answer?

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What is the rate of change of the revenue when there are 1000 downloads. So far I have R'(1000) = (130 - .019(1000))e^(-.000250(1000)). How do I calculate to get the answer?

Mathematics
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plug 1000 in for x
you'll need a scientific calculator to do that one.
I have one, but how do I type it in?

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exactly as you've written it
I don't need to put in 2.718282 anywhere?
no - just the e^x key
would I type in 130-.01981000e^-0.000150*1000
the answer I got was 130.00
well you can simplify it by doing some of it manually first 130 - .019*1000 = 130 - 19 = 111 and the exponent of e = 0.000250*1000 = 0.25 so it boils down to 111* e^(-0.25) try that one
130 is incorrect
- you didnt put the parentheses in
27.75
try again i got 86.45
dont forget the negative and the parentheses
ok, I used a different calculator and got 86.4469
yes thats right

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